How to test the opening response speed of the target website using JS-JS Tutorial-php.cn

Home

Web Front-end

JS Tutorial

How to test the opening response speed of the target website using JS

Dec 12, 2017 am 10:26 AM

javascript Open

I used JS to write a simple tool to test the opening speed of a directory website. Note that this is only the speed of opening a directory website on this machine. It does not mean that other users will open it at the same speed. In fact, it can also be used to test the speed of the local network. This article briefly explains how to use JS to test the opening response speed of the target website. The method is simple and clear for everyone to understand at a glance. I hope it can help everyone.

&lt;!DOCTYPE html PUBLIC &quot;-//W3C//DTD XHTML 1.0 Transitional//EN&quot; &quot;http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd&quot;&gt;
&lt;html xmlns=&quot;http://www.w3.org/1999/xhtml&quot;&gt;
&lt;head&gt;
&lt;meta http-equiv=&quot;Content-Type&quot; content=&quot;text/html; charset=utf-8&quot; /&gt;
&lt;title&gt;test&lt;/title&gt;
&lt;/head&gt;

&lt;body bgcolor=&quot;transparent&quot; style=&quot;color:#FFFFFF;&quot;&gt;
&lt;style type=&quot;text/css&quot;&gt;
input{font-size:12px;padding:0 5px;line-height:21px; font-family:tahoma;border:1px solid #ccc;height:21px;}                        &lt;/style&gt;
&lt;script language=&quot;javascript&quot;&gt;
tim=1
setInterval(&quot;tim++&quot;,100)
b=1
var autourl = new Array();
autourl[1] = &quot;www.qq.com&quot;;
autourl[2] = &quot;www.jb51.net&quot;;
autourl[3] = &quot;www.baidu.com&quot;;
autourl[4] = &quot;www.sina.com&quot;;

function butt(){
document.write(&quot;&lt;form name=autof style=&#39;padding:0px; margin:0px;&#39;&gt;&quot;)
for (var i = 1; i &lt; autourl.length; i++) document.write(&quot;&lt;input type=text name=txt&quot; + i + &quot; size=25 style=&#39;color:#999;&#39; value=测试中…&gt; =》&lt;input type=text name=url&quot; + i + &quot; size=40&gt; =》&lt;input type=button value=GO onclick=window.open(this.form.url&quot; + i + &quot;.value)&gt;&lt;br&gt;&quot;)
document.write(&quot;&lt;input onclick=&#39;window.location.reload()&#39; type=submit value=&#39;刷新&#39; style=&#39;margin-top:10px&#39;&gt;&lt;/form&gt;&quot;)
}
butt()
function auto(url){
document.forms[0][&quot;url&quot;+b].value=url
if(tim&gt;200)
{document.forms[0][&quot;txt&quot;+b].value=&quot;网址&quot;+b+&quot;链接超时&quot;}
else
{ document.forms[0][&quot;txt&quot; + b].value = &quot;网址&quot; + b + &quot;: 访问速度&quot; + tim * 10 + &quot;ms&quot; }
b++
}
function run(){for(var i=1;i&lt;autourl.length;i++)document.write(&quot;&lt;img src=&quot;+autourl[i]+&quot;/&quot;+Math.random()+&quot; width=1 height=1 onerror=auto(&#39;&quot;+autourl[i]+&quot;&#39;) style=&#39;display:none&#39;&gt;&quot;)}
run()
&lt;/script&gt;
&lt;/body&gt;
&lt;/html&gt;

Copy after login

The network environment of each computer is very complex, so the value obtained by this script is for reference only.

Related recommendations:

Detailed explanation of using memcache caching technology in PHP to improve response speed_PHP tutorial

JS Testing and Access CI Guide

Summary and recommendation of HTML 5 special effects page and js test page

The above is the detailed content of How to test the opening response speed of the target website using JS. For more information, please follow other related articles on the PHP Chinese website!

Statement of this Website

The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn