Home > Database > Mysql Tutorial > body text

MySQL分组排序取前N条记录 以及 生成自动数目字序列 的SQL

WBOY
Release: 2016-06-07 16:24:58
Original
1233 people have browsed it

MySQL分组排序取前N条记录 以及 生成自动数字序列 的SQL -- MySQL分组排序取前N条记录的最简洁的单条sql。 USE test; DROP TABLE IF EXISTS test; CREATE TABLE test ( id INT PRIMARY KEY, cid INT, author VARCHAR(30) ) ENGINE=MYISAM; INSERT INTO test V

MySQL分组排序取前N条记录 以及 生成自动数字序列 的SQL
-- MySQL分组排序取前N条记录的最简洁的单条sql。


USE test;


DROP TABLE IF EXISTS test;


CREATE TABLE test (
  id INT PRIMARY KEY,
  cid INT,
  author VARCHAR(30)
) ENGINE=MYISAM;


INSERT INTO test VALUES  
(1,1,'test1'),
(2,1,'test1'),
(3,1,'test2'),
(4,1,'test2'),
(5,1,'test2'),
(6,1,'test3'),
(7,1,'test3'),
(8,1,'test3'),
(9,1,'test3'),
(10,2,'test11'),
(11,2,'test11'),
(12,2,'test22'),
(13,2,'test22'),
(14,2,'test22'),
(15,2,'test33'),
(16,2,'test33'),
(17,2,'test33'),
(18,2,'test33');


INSERT INTO test VALUES  (200,200,'200test_nagios');




SELECT * FROM (SELECT cid,author,COUNT(*) AS number FROM test GROUP BY cid,author) a 
WHERE  
N>(
    SELECT COUNT(*) 
    FROM (SELECT cid,author,COUNT(*) AS number FROM test GROUP BY cid,author) b
    WHERE a.cid=b.cid AND a.number)ORDER BY cid,number DESC;


结果如下:

mysql> SELECT * FROM (SELECT cid,author,COUNT(*) AS number FROM test GROUP BY cid,author) a 
    -> WHERE  
    -> 3>(
    ->     SELECT COUNT(*) 
    ->     FROM (SELECT cid,author,COUNT(*) AS number FROM test GROUP BY cid,author) b
    ->     WHERE a.cid=b.cid AND a.number<b.number> )ORDER BY cid,number DESC;
+------+----------------+--------+
| cid  | author         | number |
+------+----------------+--------+
|    1 | test3          |      4 |
|    1 | test2          |      3 |
|    1 | test1          |      2 |
|    2 | test33         |      4 |
|    2 | test22         |      3 |
|    2 | test11         |      2 |
|  200 | 200test_nagios |      1 |
+------+----------------+--------+
7 rows in set (0.00 sec)
</b.number>
Copy after login


N就是取分组之后的最前面几个判断,N=3就是取前3个





-- 生成自动数字序列
SET @ROW=0;
SELECT a.*,(@ROW:=@ROW +1)Rank
FROM test a;

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template