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php filter_has_var 判断变量是否存在函数

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Release： 2016-06-13 11:16:47
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定义和用法
该filter_has_var （ ）函数检查，如果一个变量指定输入类型存在。

在返回TRUE或FALSE成功的失败。

语法

filter_has_var(type, variable)
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	type
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  • 
	必需的。指定类型检查可能存在的输入类型：
	INPUT_GET
    • 
	
  • INPUT_POST
    • 
	
  • INPUT_COOKIE
    • 
	
  • INPUT_SERVER
    • 
	
  • INPUT_ENV
    • 
	

			
	

	

	variable
	
	必需的。指定变量检查
	
	





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例如
在这个例子中的输入变量“名称”发送到PHP页面：
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<!--?phpif(!filter_has_var(INPUT_GET, "name")) { echo("Input type does not exist"); }else { echo("Input type exists"); }?-->
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输出为.
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 Input type exists
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                        filter has php var function judgment variable exist usage                    

                

                                
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