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php中日期加减法运算实现代码

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Release: 2016-06-13 12:03:39
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1、首先通过strtotime()获得日期的时间戳

2、获得N天前得时间戳,通过”当前时间戳 - N天的秒数 = N天前得时间戳“

3、对N天前得时间戳用date()函数进行格式转换

下例:获得2012-5-1号之前一天的日期

复制代码 代码如下:


//将时间点转换为时间戳
$date = strtotime('2012-5-1');
//输出一天前的日期,在时间戳上减去一天的秒数
echo date('Y-m-d',$date - 1*24*60*60);
?>


输出:2012-4-30

此外,time()函数获得当前日期的时间戳!
source:php.cn
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