php代码关于变量转义的有关问题

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Release: 2016-06-13 12:26:02
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php代码关于变量转义的问题

$('a.video', toolbar).click(function() {<br />			_this.save_bookmark();<br />			_this.hide_menu();<br />			$(this).xn_menu($('.video', menu), 0, 5000);<br />			setTimeout(function() {<br />				$('.video input.url', menu).focus().select();<br />			}, 100);<br />		});<br />		$('.video input.insert', menu).click(function() {<br />			var url = $('.video input.url', menu).val();<br />			var width = $('.video input.w', menu).val();<br />			var height = $('.video input.h', menu).val();<br />			_this.add_video(url, width, height);<br />			return true;<br />		});<br />		$('.video input.close', menu).click(function() {<br />			_this.hide_menu();<br />			_this.load_bookmark(true);<br />			return true;<br />		});
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this.add_video = function(url, width, height) {<br />		width = intval(width);<br />		height = intval(height);<br />		var s = "<br><br><center><script type=\"text/javascript\" src=\"jwplayer/jwplayer.js\"></script><div id=\"mediaplayer\"></div> <script type=\"text/javascript\">jwplayer('mediaplayer').setup({'flashplayer': 'jwplayer/jwplayer.flash.swf','image': 'http://7vzuer.com1.z0.glb.clouddn.com/t013d040a81b623566f.jpg', 'id': 'playerID', 'width': '100%', 'aspectratio':'10:6', 'title':'"+height+"', 'tracks':'"+width+"', 'file': '"+url+"' });</script><br><br></center>";<br />		_this.paste(s);<br />		<br />		$('div.video', _this.menu).hide();<br />	};
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以上是两个变量 width 和 height 全部被变量转换成整型变量 了,我现在两个变量输出的都是0,文字和字母输入后都不显示应该是被转换的缘故,我想请朋友帮我改改这段代码,要求输出的两个变量 width 和 height 
width 是URL形式的 height可以是文字 字幕 和数字形式(总之是去掉转型这块,代码我删除了转型的那两句但是依然还是输出的数值是0不知道怎么改了)
------解决思路----------------------
jquery获取width与height应该这样写。
var width=$("#div").width();
var height=$("#div").height();

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