How to get the parameter name of a function in php_PHP Tutorial

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Release: 2016-07-13 10:50:52
Original
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Question
How to get the parameter name of a function?
Solution
$test = 'this is a test';

$abc = 'aaaaaaaaa';

getit($test);



function getit($l){

// Get the name of $l here instead of the value

// When $test does parameter input, the string '$test' is displayed instead of the value of $test

// When $abc is used as parameter input, the string '$abc' is displayed instead of the value of $abc



}


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Reference answer
this. . Does this work?

Can't seem to get it.

Unless you read the file, use regular matching.
Reference answer
Original post by wbsifan on 2009-1-4 10:46 [url=http://bbs.111cn.cn/redirect.php?goto=findpost&pid=814417&ptid=100342]Link tag [img]http://bbs. 111cn.cn/images/common/back.gif[/img][/url]

$test = 'this is a test';
$abc = 'aaaaaaaaa';
getit($test);

function getit($l){
// Get the name of $l here instead of the value
// When $test does parameter input, the string '$test' is displayed instead of the value of $test
// When $abc ...
What’s your application?
getit('aaa');
What should be displayed? [img]http://www.111cn.cn/bbs/images/smilies/default/03.gif[/img]
Reference answer
significance. [img]http://www.111cn.cn/bbs/images/smilies/default/lol.gif[/img]
Reference answer
Don’t think about this yet...
Help me figure out how to get the parameter name...
Reference answer
Studying
Reference answer
I don’t quite understand what you mean. There is a pass-by-reference-by-value and pointer-by-value approach in C++, which may be useful to you
Reference answer




function test($val) {



if (is_array($val)){



foreach($val as $value){



$arr[]=$value;



}

return $arr;



}else {



$val = &$val;

return $val;



}



}

$val = 1;

var_dump(test($val));



echo "
";



$arr = array(1,2,3);

print_r(test($arr));





?>


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I understand what you mean but I don’t know how to implement it. I have never thought about it before. Learn·~··
Reference answer
int(1)
Array ( [0] => 1 [1] => 2 [2] => 3 )

To get the string '$arr'...that is, the parameter name instead of the parameter value..

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/632603.htmlTechArticleProblem How to get the parameter name of the function? Solution $test = 'this is a test'; $abc = ' aaaaaaaaa'; getit($test); function getit($l){ // Get the name of $l here instead of the value // When...
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