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PHP uses json_decode to force json data to be converted into an array_PHP tutorial

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Release： 2016-07-20 11:03:14
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A simple application example reference document for PHP to use json_decode to force json data to be converted into an array. We used var_dump(json_decode($str,true)); to convert json into the data we want. ​

The code is as follows Copy code
 代码如下 复制代码

$a['d'][]=1;
$a['d'][]=2;
echo $str=json_encode(array($a));
var_dump(json_decode($str));
$a['d'][]=1;

$a['d'][]=2;

echo $str=json_encode(array($a));
 代码如下 复制代码
array(1) {
  [0]=>
  object(stdClass)#1 (1) {
    ["d"]=>
    array(2) {
      [0]=>
      int(1)
      [1]=>
      int(2)
    }
  }
}
var_dump(json_decode($str));

Conversion code
 代码如下 复制代码

var_dump(json_decode($str,true));

array(1) {
  [0]=>
  array(1) {
    ["d"]=>
    array(2) {
      [0]=>
      int(1)
      [1]=>
      int(2)
    }
  }
}

See, this is an object placed in an array; Let’s force the json_decode result to be converted into an array - add the parameter

to the fourth line

The code is as follows Copy code
var_dump(json_decode($str,true));array(1) { [0]=> array(1) { ["d"]=> array(2) { [0]=> int(1) [1]=> int(2) } }
}
http://www.bkjia.com/PHPjc/445323.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/445323.htmlTechArticleA PHP simple application example reference document that uses json_decode to force json data to be converted into an array. We used var_dump(json_decode ($str,true)); Convert json into the data we want...
Related labels：
decode json php use force Replace with data array change
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