PHP array comparison function, returns true if there is intersection, otherwise returns false_PHP Tutorial

WBOY
Release: 2016-07-21 15:31:41
Original
1008 people have browsed it

Copy code The code is as follows:

$array1 = array('a', 'b', ' c', 'd');
$array2 = array('a', 'c');
$array3 = array_intersect($array1, $array2);
if($array3) {
echo 'intersection';
}
?>

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/322970.htmlTechArticleCopy the code as follows: ?php $array1 = array('a', 'b', 'c', 'd'); $array2 = array('a', 'c'); $array3 = array_intersect($array1, $array2); if($array3) { echo 'There is intersection'; } ?...
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!