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PHP array comparison function, returns true if there is intersection, otherwise returns false_PHP Tutorial

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Release: 2016-07-21 15:31:41
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Copy code The code is as follows:

$array1 = array('a', 'b', ' c', 'd');
$array2 = array('a', 'c');
$array3 = array_intersect($array1, $array2);
if($array3) {
echo 'intersection';
}
?>

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/322970.htmlTechArticleCopy the code as follows: ?php $array1 = array('a', 'b', 'c', 'd'); $array2 = array('a', 'c'); $array3 = array_intersect($array1, $array2); if($array3) { echo 'There is intersection'; } ?...
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