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PHP extracts the image address in the database content and loops the output_PHP tutorial

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Release： 2016-07-21 15:39:57
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Copy code The code is as follows:

/*
1 (?s) represents Pattern.DOTALL, which means matching newlines, allowing
2 .*? appearing in multiple lines in img means non-greedy matching of any character until the subsequent condition appears
3 ?: means this match but is not captured, that is, it does not appear in the result [.gif|.jpg ] means or
*/
$pattern="//";
$str='

';
preg_match_all($pattern,$str,$match);
print_r($match);
/*
Array
(
[0] => Array
(
[0] => =""/>
[1] =>
[2] = >
)
[1] => Array
(
[0] => upfiles/2009/07/1246430143_4.jpg
[1] => upfiles/2009/07/1246430143_3.jpg
[2] => upfiles/2009/07/1246430143_1 .jpg
)
)
*/

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/321480.htmlTechArticleCopy the code as follows: /* 1 (?s) represents Pattern.DOTALL, which matches newlines and allows img appears in multiple lines 2.*? means non-greedy matching of any character until the following condition appears...
Related labels：
php code represent content picture address copy cycle extract database output
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