Article Topic Learning Download Q&A Programming Dictionary Game Recent Updates

简体中文(ZH-CN) English(EN) 繁体中文(ZH-TW) 日本語(JA) 한국어(KO) Melayu(MS) Français(FR) Deutsch(DE)

Home > Backend Development > PHP Tutorial > body text

PHP code to determine whether the visitor is a search engine or a real user

WBOY

Release： 2016-07-25 09:00:03

Original

1638 people have browsed it

/**
* Determine whether the access source is a search engine or a real user
* site bbs.it-home.org
*/
function is_bot()
{
/* This function will check whether the visitor is a search engine robot */
//根据需要扩充此数组
$botlist = array("Teoma", "alexa", "froogle", "Gigabot", "inktomi",
"looksmart", "URL_Spider_SQL", "Firefly", "NationalDirectory",
"Ask Jeeves", "TECNOSEEK", "InfoSeek", "WebFindBot", "girafabot",
"crawler", "bbs.it-home.org", "Googlebot", "Scooter", "Slurp",
"msnbot", "appie", "FAST", "WebBug", "Spade", "ZyBorg", "rabaz",
"Baiduspider", "Feedfetcher-Google", "TechnoratiSnoop", "Rankivabot",
"Mediapartners-Google", "Sogou web spider", "WebAlta Crawler","TweetmemeBot",
"Butterfly","Twitturls","Me.dium","Twiceler");
foreach($botlist as $bot)
{
if(strpos($_SERVER['HTTP_USER_AGENT'],$bot)!==false)
return true; // Is a bot
}
return false; // Not a bot
}
?>

复制代码

Related labels：

php判断访问者是搜索引擎还是真实用户的代码

source：php.cn

Previous article：Simple example of php sphinx Next article：What newbies in php should know

Statement of this Website

The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn