Code
Copy code The code is as follows:
$url = 'www.baidu.com'; //Catch Baidu
echo snapshot($url); //The output result is a picture Address
echo snapshot($url, './baidu.png'); //Save the image to local baidu.png, output content image size
/**
* Generate web page snapshot
*
* @param string $site target address
* @param string $path Save address, if it is empty, it will not be saved
* @param integer $dealy Delay
* @return mixed Return according to parameters
*/
function snapshot($site, $path = '', $dealy = 0)
{
$url = 'http://ppt.cc/yo2/catch.php';
$query = 'url=' . $site . '&delay=' . $dealy . '&rnd=' . mt_rand(1, 9);
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $query);
curl_setopt($ ch, CURLOPT_USERAGENT, $_SERVER['HTTP_USER_AGENT']);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$data = curl_exec($ch);
curl_close($ch);
if (strlen($data) ! = 32) {
exit('Invalid URL');
}
$file = $data{0} . '/' . $data{1} . '/' . $data{2} . '/';
$file = 'http://cache.ppt.cc/' . $file . 'src_' . $data . '.png';
if (!empty($path)) {
$data = file_get_contents($file );
return file_put_contents($path, $data);
}
return $file;
}
?>
The above introduces where the web page snapshot is. PHP generates web page snapshot without using COM or extension. It includes the content of where the web page snapshot is. I hope it will be helpful to friends who are interested in PHP tutorials.