php recursive parsing

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Release: 2016-08-08 09:24:12
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function test($i){//第一步
	$i  -= 4; 
	if($i<3){ 
		return $i; //第二部
	}else{ 
		test($i); //第三部
	} 
} 
echo test(10); 
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function test($i){//第一步
<span style="white-space:pre">	</span>$i  -= 4; 
<span style="white-space:pre">	</span>if($i<3){ 
<span style="white-space:pre">		</span>return $i; //第二步
<span style="white-space:pre">	</span>}else{ 
<span style="white-space:pre">		</span>function test($i){//第 3步
<span style="white-space:pre">			</span>$i  -= 4; 
<span style="white-space:pre">			</span>if($i<3){ 
<span style="white-space:pre">				</span>return $i; //第4步
<span style="white-space:pre">			</span>}else{ 
<span style="white-space:pre">				</span>test();//第5步
<span style="white-space:pre">			</span>} 
<span style="white-space:pre">		</span>} 
<span style="white-space:pre">	</span>} 
} 
echo test(30); 
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上面的的第一段代码作为例子<p>写这样代码的人可以没完全理解递推,</p><p>下面使用test(10)调用,在执行过程中,如果条件成立,则直接返回结果,</p><p>如果条件不成立则继续调用test(),猛一看这样写没问题,其实,当第一次调用条件不成立时再调用一次时,即使成立也没用返回值,第二段代码是两次调的结果:</p><p>假如在第二次调用,代码执行到第四步时结果成立,他的动作是return 2;  现在代码成什么样子了呢,看下面
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function test($i){//第一步
	$i  -= 4; 
	if($i<3){ 
		return $i; //第二部
	}else{ 
		2;
	} 
} 
echo test(10); 
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There is only a single 2. How does it return to the bottom? A return must be added in front;

So the complete code should be like this.

function test($i){//第一步
	$i  -= 4; 
	if($i<3){ 
		return $i; //第二部
	}else{ 
		return test($i);
	} 
} 
echo test(10); 
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The above has introduced PHP recursive parsing, including aspects of it. I hope it will be helpful to friends who are interested in PHP tutorials.

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