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Detailed explanation of Threadpool thread pool task termination sample code in python
Detailed explanation of Threadpool thread pool task termination sample code in python
Requirements
Join us and we need to process a series of single digits (0~9). If it is an odd number, we need to loop to print it; if it is an even number, wait for the corresponding time and complete all tasks; if it is 0 It is an error, but there is no need to terminate the task and some processing can be customized.
Key points
Define funcFunctionProcessing requirements
Callback processing returns results, only even numbers and 0 are returned; odd numbers will always be executed; thread control is required Pool status , you need to throw an exception for even numbers and 0, and capture exception handling .
threadpool defines thread pool concurrency
Implementation
# -*- coding: utf-8 -*- from threadpool import makeRequests, ThreadPool import time from multiprocessing import Process
Exception definition and special value (0) definition
class Finish(SyntaxWarning): pass
class PauseInfo(SyntaxWarning): pass pause_num = 0
func function definition
Returns False when 0, returns True for other even numbers
def func(para):
if para == pause_num:
print('start for %d and wait %ds' % (para, 4))
time.sleep(4)
print('error bcs ',para)
return False
if para % 2 == 0:
print('start for %d and wait %ds' % (para, para))
time.sleep(para)
print('stop for', para)
return True
while True:
print('continue for', para)
time.sleep(para)callback definition
def callback(request, result): if result: raise Finish else: raise PauseInfo
Thread pool processing
Finish marks the completion of the task, and induces an exception again to exit the thread pool processing;
def main_thread(paras):
pool = ThreadPool(10)
requests = makeRequests(callable_=func, args_list=paras, callback=callback)
[pool.putRequest(req) for req in requests]
while True:
try:
pool.wait()
except Finish as e:
raise SystemExit
except PauseInfo as e:
print('Pause bcs %d but will continue' % pause_num)
except Exception as e:
print('Unknown error so will quit')
raise SystemExitThe main function starts a test process
if name == 'main':
while True:
s = input('Input number list to test and any other word to quit\n')
paras = []
for para in s:
if para.isnumeric():
paras.append(int(para))
else:
break
try:
thread_test = Process(target=main_thread, args=(paras,))
thread_test.start()
thread_test.join(timeout=20)
except TimeoutError as e:
print('task timeout')
except Exception as e:
print('unknow error:',e)Result verification
Processing 108, you can see from the print that 1 is processed in a loop, and an error is reported when 0 is processed; 8 is processed and the task End
Input number list to test and any other word to quit
108
continue for 1
start for 0 and wait 4s
start for 8 and wait 8s
continue for 1
continue for 1
continue for 1
error bcs 0
continue for 1
Pause bcs 0 but will continue
continue for 1
continue for 1
continue for 1
continue for 1
stop for 8
Input number list to test and any other word to quit
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