Example of the function of finding data files based on file names implemented in Python-Python Tutorial-php.cn

Example of the function of finding data files based on file names implemented in Python

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Release： 2018-05-02 14:11:58

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这篇文章主要介绍了Python实现的根据文件名查找数据文件功能,涉及Python针对文件与目录的遍历、查询等相关操作技巧,需要的朋友可以参考下

本文实例讲述了Python实现的根据文件名查找数据文件功能。分享给大家供大家参考，具体如下：

#-*- coding: UTF-8 -*-
import os
import shutil
AllFiles=[]
NameFiles=[]
def findFie(filePath):
 pathDir = os.listdir(filePath)
 for allDir in pathDir:
  # print(allDir)
  AllFiles.append(allDir)
  #pass
#filepath = &#39;C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71\\71sns&#39;
#copyfile = &#39;C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\71mtp&#39;
filepath = &#39;C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72\\72sns&#39;
copyfile = &#39;C:\\Users\\IBM_ADMIN\\Desktop\\cognos\\datastage\\71&72\\72mtp&#39;
shutil.rmtree(copyfile)
os.mkdir(copyfile)
findFie(filepath)
def readFile():
 readFile = open(&#39;./jobname&#39;)
 i = 0
 for eachLine in readFile:
  i= i + 1
  #print(eachLine)
  NameFiles.append(eachLine.replace(&#39;\n&#39;,&#39;&#39;)) # 去掉换行符
readFile()
#字符串比较
def doTheCompare():
 for x in NameFiles:
  print(x)
  for y in AllFiles:
   if x == y :
    copyFrom = os.path.join(filepath,x)
    copyTo = os.path.join(copyfile,x)
    shutil.copyfile(copyFrom,copyTo)
   else:
    pass
    #print ("file not find under sns process,thanks .please check with wumi.")
doTheCompare()

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附：这里再补充一个更为简单的文件搜索功能示例：

# -*- coding:utf-8 -*-
import os
def search(path=".", name="1"):
  for item in os.listdir(path):
    item_path = os.path.join(path, item)
    if os.path.isdir(item_path):
      search(item_path, name)
    elif os.path.isfile(item_path):
      if name in item:
        print(item_path)
if __name__ == "__main__":
  search(path=r"D:\360Downloads",name="dll")

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