算法 - 一道python题目:如何把元组编程字典?

Question

问题: 我有一个元组列表: 现在我想把这组元组变成字典的列表,类似的效果是这样: {代码...} 有什么比较方便的方法?

怪我咯 · Answer

@dokelung 的方法可以更简洁

names = 'area brand question price'.split()
lst = [dict(zip(names, t)) for t in tlst]

大家讲道理 · Answer

names = 'area brand question price'.split()
lst = [{name:value for name, value in zip(names, t)} for t in tlst]

測試:

tlst = [('a1','b1','q1','p1'),
        ('a2','b2','q2','p2'),
        ('a3','b3','q3','p3')]
 
names = 'area brand question price'.split()
lst = [{name:value for name, value in zip(names, t)} for t in tlst]

print(lst)

結果:

[{'brand': 'b1', 'area': 'a1', 'question': 'q1', 'price': 'p1'}, {'brand': 'b2', 'area': 'a2', 'question': 'q2', 'price': 'p2'}, {'brand': 'b3', 'area': 'a3', 'question': 'q3', 'price': 'p3'}]

我回答過的問題: Python-QA

迷茫 · Answer

简单的写法：(a是元组组成的数组)

meat = [{'地区词':t[0], '品牌词':t[1], '疑问词':t[2], '价格词':t[3]} for t in a]

当然你也可以试试用映射的方法，这里不写了

天蓬老师 · Answer

为了强行装逼，使用$lambda$表达式写个：

list(map(lambda x: {'地区词':x[0], '品牌词':x[1], '疑问词':x[2], '价格词':x[3]}, a))

请忽略我的答案。。。

迷茫 · Answer

楼上正解组成单独的字典，然后调用数组的append 就ok了

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