Correction status:qualified
Teacher's comments:写得很认真, 望坚持下去
1、form.html
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8" /> <title>Ajax</title> <script type="text/javascript" src="jquery-3.4.1.min.js"></script> </head> <style> div{margin:10px;text-align: center;} </style> </head> <body> <form method="post" action="./ajax.php"> <div style="text-align: center;"> <label for="">用户名:</label> <input type="text" name="username" /> </div> <div style="text-align: center;"> <label for="">密码:</label> <input type="password" name="pwd" /> </div> <div style="text-align: center;"> <label for="">验证码</label> <input type="text" name="vericode" /> </div> <div> <button type="button" onclick="save()">提交</button> </div> </form> <script type="text/javascript"> function save(){ var username=$.trim($('input[name="username"]').val()); var pwd=$.trim($('input[name="pwd"]').val()); var vericode=$.trim($('input[name="vericode"]').val()); if(username==''){ alert('请输入用户名'); return; } if(pwd==''){ alert('请输入密码'); return; } if(vericode==''){ alert('请输入验证码'); return; } $.post('./ajax.php',{username:username,pwd:pwd,vericode:vericode},function(data){ if(data.code>0){ alert(data.msg); return; } alert(data.msg); window.location.href="http://www.php.cn"; },'json'); } </script> </body> </html>
点击 "运行实例" 按钮查看在线实例
ajax.php
<?php $username=$_POST['username']; $pwd=$_POST['pwd']; $verify=$_POST['vericode']; if($verify!='123'){ exit(json_encode(array('code'=>1,'msg'=>'验证码错误'))); } if($username!="admin"){ exit(json_encode(array('code'=>1,'msg'=>'用户名错误'))); } if($pwd!="123456"){ exit(json_encode(array('code'=>1,'msg'=>'密码错误'))); } exit(json_encode(array('code'=>0,'msg'=>'登录成功')));
点击 "运行实例" 按钮查看在线实例
运行效果图