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ajax验证表单
PHP小学生
Original
717 people have browsed it
这是login.html
<!DOCTYPE html>
<html>
<head>
   <meta charset="UTF-8">
   <title>ajax验证手机号</title>
</head>
<body>
<ul>
   <li>用户名<input type="text" name="userName" ><span></span></li>
   <li>密码<input type="password" name="password" ><span></span></li>
   <button>登陆</button>
</ul>
<script>
   var user = document.getElementsByName('userName')[0]
   var password = document.getElementsByName('password')[0]
   var btn = document.getElementsByTagName('button')[0]
   // 第一步：给用户名添加blur事件，当鼠标离开用户名时候触发
user.onblur = function () {
       // 1.创建ajax对象
var  xhr = new XMLHttpRequest()
       // 2.监听ajax对象响应事件
xhr.onreadystatechange = function () {
           //响应成功
if (xhr.readyState == 4) {
               user.nextSibling.innerHTML = this.responseText
           }
       }
       // 3.初始化ajax请求
// 创建查询参数，验证用户名
var data = '?userName='+user.value
xhr.open('get','check.php'+data, true)
       // 4.发送请求
xhr.send(null)
   }
   // 第二步：给密码框添加blur事件，当鼠标离开密码框时候触发
password.onblur = function () {
       // 1.创建ajax对象
var xhr = new XMLHttpRequest()
       // 2.监听ajax事件
xhr.onreadystatechange = function () {
           if (xhr.readyState == 4){
               password.nextSibling.innerHTML = this.responseText
           }
       }

       // 3.初始化ajax请求
var data = '?password'+password.value
xhr.open('get','check.php'+data,true)
       // 4.发送请求
xhr.send(null)
   }
   // 登陆按钮
btn.onclick = function () {
       alert('恭喜登陆成功')
   }
</script>
</body>
</html>

这是check.php文件，包含了返回的text

<?php
/**
 * Created by PhpStorm.
 * User: 葛浮东
 * Date: 2017/12/20
 * Time: 0:22
 */
$userName = isset($_GET['userName']) ? $_GET['userName']:null;
$userList=['123','456','789'];
if($userName !== null){
    if(in_array($userName,$userList)){
        echo '用户名重复';
    }else{
        echo '用户名可用';
    }
}
$password = isset($_GET['password']) ? $_GET['password']:null;
if ($password!==null){
    if(strlen($password)>=6){
        echo '密码复合要求';
    }else{
        echo '密码不符合要求';
    }
}
?>


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