Blogger Information
Blog 14
fans 0
comment 0
visits 12184
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
Ajax原生实现方式
JUNL的博客1111
Original
682 people have browsed it

实例

<!DOCTYPE html>
<html lang="en">
<head>
	<meta charset="UTF-8">
	<title>Ajax入门</title>
</head>
<body>
	<!--<h2>Ajax</h2>-->
	<form action ="api/check.php" method="post">
	<fieldset>
		<legend>用户登录</legend>
		<p>
			<lable for="email">邮箱:</lable>
			<input type="text" name=""email" id="email">
		</p>
		<p>
			<lable for="password">密码:</lable>
			<input type="password" name="password" id="password">
		</p>
		<p><button>登录</button>
		<span id="tips" style="font-size:1.2em;font-weight:bolder;color:red;"></span>
	</p>
	</fieldset>
	</form>
</body>
</html>
<!--<script type="text/javascript" src="http://apps.bdimg.com/libs/jquery/2.1.4/jquery.min.js"></script>-->
<script type="text/javascript">
	var btn=document.getElementsByTagName('button')[0]
	btn.onclick=function(){
		//alert('登录成功')
		//获取用户提交的数据
		var email=document.getElementById('email').value
		var password=document.getElementById('password').value
		//将用户数据拼装成查询字符串
		var data='email='+email+'&password='+password  
		//1创建 XHR对象
		var xhr =new XMLHttpRequest()
		//2.事件监听
		xhr.onreadystatechange=function(){
			
			if (xhr.readyState == 4 && xhr.status == 200){
			var tips =document.getElementById('tips')
		if(xhr.responseText =='1'){
			tips.innerHTML='登录成功,正在跳转。。'

			setTimeout(function(){
				location.href='api/index.php'},2000)
		

			}else{
				tips.innerHTML='邮箱或密码错误码。。。'
			document.getElementById('email').focus()
			//setTimeout(function(){location.href='api/index.php'},2000)}
			setTimeout("tips.innerHtml=''",2000)
		}
	}
		


		}
		//3 建立连接
		xhr.open('POST','api/user.php?m=login',true)
		//4 发送请求
		xhr.setRequestHeader('content-type','application/x-www-form-urlencoded')
		xhr.send(data)
		//5 设置回调函数
		//DOM操作



 return false
}
</script>

运行实例 »

点击 "运行实例" 按钮查看在线实例

实例

<?php 
echo '<h1 style="color:red">登录成功</h1>';

运行实例 »

点击 "运行实例" 按钮查看在线实例

实例

<?php 
if ($_GET['m'] == 'login') {
	if ($_POST['email'] == 'admin@php.cn' && $_POST['password'] == '123456'){
			echo '1';
		}
	else {
		echo '0';
	}
}

运行实例 »

点击 "运行实例" 按钮查看在线实例


Statement of this Website
The copyright of this blog article belongs to the blogger. Please specify the address when reprinting! If there is any infringement or violation of the law, please contact admin@php.cn Report processing!
All comments Speak rationally on civilized internet, please comply with News Comment Service Agreement
0 comments
Author's latest blog post