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ajax表单验证实例——2018年9月19日
图图的博客
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实例

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Ajax实战:表单验证</title>
</head>
<body>
<h3>用户登录</h3>
<form>
    <p>邮箱: <input type="email" name="email"></p>
    <p>密码: <input type="password" name="password"></p>
    <p><button type="button">提交</button></p>
</form>
<script>
    let btn = document.getElementsByTagName('button')[0];
    btn.onclick = function () {
        //1.创建xhr对象
        let xhr = new XMLHttpRequest();

        //2.监听响应状态
        xhr.onreadystatechange = function(){
            if (xhr.readyState === 4) { // 准备就绪
                // 判断响应结果:
                if (xhr.status === 200) {
                    // 响应成功,通过xhr对象的responseText属性可以获取响应的文本,此时是html文档内容
                    let p = document.createElement('p');  //创建新元素放返回的内容
                    p.style.color = 'red';

                    let json = JSON.parse(xhr.responseText);
                    if (json.status === 1) {
                        p.innerHTML = json.msg;

                    } else if (json.status == 0) {
                        p.innerHTML = json.msg;
                    }
                    // 将响应文本添加到新元素上
                    document.forms[0].appendChild(p); // 将新元素插入到当前页面中
                    btn.disabled = true;
                    setTimeout(function(){
                        document.forms[0].removeChild(p);
                        btn.disabled = false;
                        if (json.status == 1) {
                            location.href = 'admin.php';
                        }
                    },2000);
                } else {
                    // 响应失败,并根据响应码判断失败原因
                    alert('响应失败'+xhr.status);
                }
            } else {
                // http请求仍在继续,这里可以显示一个一直转来转去的图片
            }

        }

        //3.设置请求参数
        xhr.open('post','check.php',true);

        //4. 设置头信息,将内容类型设置为表单提交方式
        xhr.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');

        //4.发送请求
        let data = {
            email:  document.getElementsByName('email')[0].value,
            password:  document.getElementsByName('password')[0].value
        };
        // data = 'email='+data.email+'&password='+data.password;
        let data_json=JSON.stringify(data);
        xhr.send('data='+data_json);
    }
</script>
</body>
</html>

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实例

<?php

//print_r($_POST['data']);
//echo $data['email'];


$user = json_decode($_POST['data']);
//echo $user->email;
$email = $user->email;
$password = sha1($user->password);

$pdo = new PDO('mysql:host=localhost;dbname=php','root','root');

$sql = "SELECT COUNT(*) FROM `user` WHERE `email`='{$email}' AND `password`='{$password}' ";

$stmt = $pdo->prepare($sql);

$stmt->execute();

if ($stmt->fetchColumn() == 1) {
    echo json_encode(["status"=>1,"msg"=>"登录成功,正在跳转..."]) ;
    exit;
} else {
    echo json_encode(["status"=>0,"msg"=>"邮箱或密码错误,登录失败!"]) ;
    exit;
}

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Correction status:qualified

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