PHP - AJAX and MySQL
AJAX can be used to communicate interactively with the database.
AJAX database instance
The following example will demonstrate How a web page reads information from the database through AJAX:
html page display
Explanation of examples - MySQL database
In the above example, the database table we use is as follows:
Explanation of examples - HTML page
When the user selects a user in the drop-down list above, the function named "showUser()" will be executed. This function is triggered by the "onchange" event:
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Title</title> <script> function showUser(str) { if (str=="") { document.getElementById("txtHint").innerHTML=""; return; } if (window.XMLHttpRequest) { // IE7+, Firefox, Chrome, Opera, Safari 浏览器执行代码 xmlhttp=new XMLHttpRequest(); } else { // IE6, IE5 浏览器执行代码 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("txtHint").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","getuser.php?q="+str,true); xmlhttp.send(); } </script> </head> <body> <form> <select name="users" onchange="showUser(this.value)"> <option value="">Select a person:</option> <option value="1">John Doe</option> <option value="2">tom Mary</option> <option value="3">lijing liuqi</option> <option value="4">liu li</option> </select> </form> <br> <div id="txtHint"><b>数据库信息展示在这</b></div> </body> </html>
showUser() function will perform the following steps:
· Check whether a user is selected
· Create an XMLHttpRequest object
· Create a function that executes when the server response is ready
· Send a request to a file on the server
· Please note the parameter (q) added to the end of the URL (including the drop-down list Content)
PHP file
The server page called above through JavaScript is a PHP file named "database" .
The source code in database.php" will run a query against the MySQL database and return the results in an HTML table:
database.php file
<?php $q=$_GET["q"]; $con = mysqli_connect('localhost','root','root','test'); if (!$con) { die('Could not connect: ' . mysqli_error($con)); } //mysqli_select_db($con,"ajax_demo"); $sql="SELECT * FROM Myguests WHERE id = '".$q."'"; $result = mysqli_query($con,$sql); echo "<table border='1'> <tr> <th>firstname</th> <th>lastname</th> <th>email</th> <th>Age</th> </tr>"; while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['firstname'] . "</td>"; echo "<td>" . $row['lastname'] . "</td>"; echo "<td>" . $row['email'] . "</td>"; echo "<td>" . $row['Age'] . "</td>"; ; echo "</tr>"; } echo "</table>"; mysqli_close($con); ?>
Explanation: When a query is sent from JavaScript to a PHP file, what happens is:
1. PHP opens a connection to the MySQL database
2. Found Selected user
3. Create an HTML table, fill in the data, and send back the "txtHint" placeholder
Program results display: