Wie sortiere ich eine verschachtelte Liste basierend auf inneren Listenelementen?

Sorting Nested Lists Based on Inner List Elements

Nested lists are ubiquitous in programming, and handling them requires adept data manipulation techniques. One such scenario involves sorting the outer list based on specific indices within the inner lists. Fortunately, the following solutions offer effective ways to tackle this challenge:

Using itemgetter

The itemgetter function from the operator module provides a concise solution. It allows you to extract specific elements from each inner list and sort the outer list based on those extracted elements.

from operator import itemgetter

L = [[0, 1, 'f'], [4, 2, 't'], [9, 4, 'afsd']]
sorted(L, key=itemgetter(2))
# [[9, 4, 'afsd'], [0, 1, 'f'], [4, 2, 't']]

Using a lambda function

Although slightly less efficient in this simple case, a lambda function can also accomplish the sorting:

sorted(L, key=lambda x: x[2])
# [[9, 4, 'afsd'], [0, 1, 'f'], [4, 2, 't']]

By leveraging itemgetter or a lambda function, you can effectively sort nested lists based on specific indices of their inner elements, thereby enhancing your data processing capabilities.

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