Vor-, Mittel- und Nachname aus dem Feld „Vollständiger Name“ mit SQL analysieren
Bei der Datenverarbeitung ist es oft notwendig, Namen in ihre Namen zu unterteilen Einzelteile zur einfacheren Handhabung. In diesem Fall müssen wir den Vor-, Mittel- und Nachnamen aus einem Feld „vollständiger Name“ extrahieren und dabei häufige Datenvariationen berücksichtigen.
Effiziente Lösung mit 90 % Genauigkeit
Das bereitgestellte Beispiel bietet eine praktische Lösung, die die meisten Fälle mit einem hohen Maß an Genauigkeit behandelt:
SELECT FIRST_NAME.ORIGINAL_INPUT_DATA, FIRST_NAME.TITLE, FIRST_NAME.FIRST_NAME, CASE WHEN 0 = CHARINDEX(' ', FIRST_NAME.REST_OF_NAME) THEN NULL -- No more spaces? Assume rest is last name ELSE SUBSTRING(FIRST_NAME.REST_OF_NAME, 1, CHARINDEX(' ', FIRST_NAME.REST_OF_NAME) - 1) END AS MIDDLE_NAME, SUBSTRING(FIRST_NAME.REST_OF_NAME, 1 + CHARINDEX(' ', FIRST_NAME.REST_OF_NAME), LEN(FIRST_NAME.REST_OF_NAME)) AS LAST_NAME FROM ( SELECT TITLE.TITLE, CASE WHEN 0 = CHARINDEX(' ', TITLE.REST_OF_NAME) THEN TITLE.REST_OF_NAME -- No space? Return the whole thing ELSE SUBSTRING(TITLE.REST_OF_NAME, 1, CHARINDEX(' ', TITLE.REST_OF_NAME) - 1) END AS FIRST_NAME, CASE WHEN 0 = CHARINDEX(' ', TITLE.REST_OF_NAME) THEN NULL -- No spaces at all? Then 1st name is all we have ELSE SUBSTRING(TITLE.REST_OF_NAME, CHARINDEX(' ', TITLE.REST_OF_NAME) + 1, LEN(TITLE.REST_OF_NAME)) END AS REST_OF_NAME, TITLE.ORIGINAL_INPUT_DATA FROM ( SELECT -- If the first three characters are in this list, -- then pull it as a "title". Otherwise return NULL for title. CASE WHEN SUBSTRING(TEST_DATA.FULL_NAME, 1, 3) IN ('MR ', 'MS ', 'DR ', 'MRS') THEN LTRIM(RTRIM(SUBSTRING(TEST_DATA.FULL_NAME, 1, 3))) ELSE NULL END AS TITLE, -- If you change the list, don't forget to change it here, too. CASE WHEN SUBSTRING(TEST_DATA.FULL_NAME, 1, 3) IN ('MR ', 'MS ', 'DR ', 'MRS') THEN LTRIM(RTRIM(SUBSTRING(TEST_DATA.FULL_NAME, 4, LEN(TEST_DATA.FULL_NAME)))) ELSE LTRIM(RTRIM(TEST_DATA.FULL_NAME)) END AS REST_OF_NAME, TEST_DATA.ORIGINAL_INPUT_DATA FROM ( SELECT -- Trim leading & trailing spaces before trying to process -- Disallow extra spaces *within* the name REPLACE(REPLACE(LTRIM(RTRIM(FULL_NAME)), ' ', ' '), ' ', ' ') AS FULL_NAME, FULL_NAME AS ORIGINAL_INPUT_DATA FROM ( -- Replace this block with your actual table SELECT 'GEORGE W BUSH' AS FULL_NAME UNION SELECT 'SUSAN B ANTHONY' AS FULL_NAME UNION SELECT 'ALEXANDER HAMILTON' AS FULL_NAME UNION SELECT 'OSAMA BIN LADEN JR' AS FULL_NAME UNION SELECT 'MARTIN J VAN BUREN SENIOR III' AS FULL_NAME UNION SELECT 'TOMMY' AS FULL_NAME UNION SELECT 'BILLY' AS FULL_NAME ) RAW_DATA ) TEST_DATA ) TITLE ) FIRST_NAME;
Diese Abfrage identifiziert und Entfernt Präfixe wie „MR“, „MS“, „DR“ und „MRS“ als separate „TITLE“-Spalten, behandelt fehlende Namen, mehrere Leerzeichen im Namen und einen einteiligen „vollständigen Namen“ (nur Vorname). .
Umgang mit Sonderfällen
Die Lösung umfasst auch eine Änderung, die bestimmte Sonderfälle berücksichtigt, wie z. B. ein leeres Feld „vollständiger Name“, Nachgestellte/führende Leerzeichen, mehrere aufeinanderfolgende Leerzeichen und ein „vollständiger Name“, der nur den Vornamen enthält:
-- Handle the following special cases: -- 1 - The NAME field is NULL -- 2 - The NAME field contains leading / trailing spaces -- 3 - The NAME field has > 1 consecutive space within the name -- 4 - The NAME field contains ONLY the first name -- 5 - Include the original full name in the final output as a separate column, for readability -- 6 - Handle a specific list of prefixes as a separate "title" column SELECT FIRST_NAME.ORIGINAL_INPUT_DATA, FIRST_NAME.TITLE, FIRST_NAME.FIRST_NAME, CASE WHEN 0 = CHARINDEX(' ', FIRST_NAME.REST_OF_NAME) THEN NULL -- No more spaces? Assume rest is last name ELSE SUBSTRING(FIRST_NAME.REST_OF_NAME, 1, CHARINDEX(' ', FIRST_NAME.REST_OF_NAME) - 1) END AS MIDDLE_NAME, SUBSTRING(FIRST_NAME.REST_OF_NAME, 1 + CHARINDEX(' ', FIRST_NAME.REST_OF_NAME), LEN(FIRST_NAME.REST_OF_NAME)) AS LAST_NAME FROM ( SELECT TITLE.TITLE, CASE WHEN 0 = CHARINDEX(' ', TITLE.REST_OF_NAME) THEN TITLE.REST_OF_NAME -- No space? Return the whole thing ELSE SUBSTRING(TITLE.REST_OF_NAME, 1, CHARINDEX(' ', TITLE.REST_OF_NAME) - 1) END AS FIRST_NAME, CASE WHEN 0 = CHARINDEX(' ', TITLE.REST_OF_NAME) THEN NULL -- No spaces at all? Then 1st name is all we have ELSE SUBSTRING(TITLE.REST_OF_NAME, CHARINDEX(' ', TITLE.REST_OF_NAME) + 1, LEN(TITLE.REST_OF_NAME)) END AS REST_OF_NAME, TITLE.ORIGINAL_INPUT_DATA FROM ( SELECT -- If the first three characters are in this list, -- then pull it as a "title". Otherwise return NULL for title. CASE WHEN SUBSTRING(TEST_DATA.FULL_NAME, 1, 3) IN ('MR ', 'MS ', 'DR ', 'MRS') THEN LTRIM(RTRIM(SUBSTRING(TEST_DATA.FULL_NAME, 1, 3))) ELSE NULL END AS TITLE, -- If you change the list, don't forget to change it here, too. CASE WHEN SUBSTRING(TEST_DATA.FULL_NAME, 1, 3) IN ('MR ', 'MS ', 'DR ', 'MRS') THEN LTRIM(RTRIM(SUBSTRING(TEST_DATA.FULL_NAME, 4, LEN(TEST_DATA.FULL_NAME)))) ELSE LTRIM(RTRIM(TEST_DATA.FULL_NAME)) END AS REST_OF_NAME, TEST_DATA.ORIGINAL_INPUT_DATA FROM ( SELECT -- Trim leading & trailing spaces before trying to process -- Disallow extra spaces *within* the name REPLACE(REPLACE(LTRIM(RTRIM(FULL_NAME)), ' ', ' '), ' ', ' ') AS FULL_NAME, FULL_NAME AS ORIGINAL_INPUT_DATA FROM ( -- Replace this block with your actual table SELECT 'GEORGE W BUSH' AS FULL_NAME UNION SELECT 'SUSAN B ANTHONY' AS FULL_NAME UNION SELECT 'ALEXANDER HAMILTON' AS FULL_NAME UNION SELECT 'OSAMA BIN LADEN JR' AS FULL_NAME UNION SELECT 'MARTIN J VAN BUREN SENIOR III' AS FULL_NAME UNION SELECT 'TOMMY' AS FULL_NAME UNION SELECT 'BILLY' AS FULL_NAME UNION SELECT NULL AS FULL_NAME UNION SELECT ' ' AS FULL_NAME UNION SELECT ' JOHN JACOB SMITH' AS FULL_NAME UNION SELECT ' DR SANJAY GUPTA' AS FULL_NAME UNION SELECT 'DR JOHN S HOPKINS' AS FULL_NAME UNION SELECT ' MRS SUSAN ADAMS' AS FULL_NAME UNION SELECT ' MS AUGUSTA ADA KING ' AS FULL_NAME ) RAW_DATA ) TEST_DATA ) TITLE ) FIRST_NAME;
Das obige ist der detaillierte Inhalt vonWie kann ich Vor-, Zweit- und Nachnamen effizient aus einem einzigen Feld „vollständiger Name' in SQL analysieren und dabei verschiedene Dateninkonsistenzen und Sonderfälle bewältigen?. Für weitere Informationen folgen Sie bitte anderen verwandten Artikeln auf der PHP chinesischen Website!