mysql 的查询嵌套有关问题

mysql 的查询嵌套问题。

SQL code

<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->select a.*,  d.sell_countfrom borough as a left join (  select da.* from (    select count(db.id) as sell_count,db.borough_id from housesell as db      where db.borough_id = a.id    ) as da  ) as dwhere a.is_checked = 1 order by id desc LIMIT 0, 10

请问，left join 里面的
where db.borough_id = a.id 这一句会报错。请问大家有什么方式来实现嘛。



------解决方案--------------------
把ORDER BY a.id 改成group by

SQL code

SELECT a.*,  COUNT(db.id) AS sell_count FROM  borough AS a LEFT JOIN housesell AS db ON( db.borough_id = a.id)WHERE a.is_checked = 1 GROUP BY a.idORDER BY id DESC LIMIT 0, 10<div class="clear">
                 
              
              
        
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