PHP 表单传递参数与获取参数有关问题-PHP-Tutorial-php.cn

PHP 表单传递参数与获取参数有关问题

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Freigeben： 2016-06-13 12:02:33

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PHP 表单传递参数与获取参数问题

<html><br /><head><title>Register</title></head><br /><body><br />	<?php<br />	if (!isset($_POST['register1']) || ( $_POST['register1'] != 'Register'))<br />	{<br />			#echo "test1";<br />	?><br />	<h1>Registration</h1><br />	<form method = "post" action = "register.php"><br />		<table><br />			<tr><td>E-mail address:</td><br />				<td><input type='text' name = 'email'/></td><br />			</tr><br />			<tr><td>First Name:</td><br />				<td><input type = 'text' name = 'first_name'/></td><br />			</tr><br />			<tr><td>Last Name:</td><br />				<td><input type = 'text' name = 'last_name'/></td><br />			</tr><br />			<tr><td>PassWord:</td><br />				<td><input type = 'password' name = 'password'/></td><br />			</tr><br /><br />			<tr><br />				<td colspan = '2'><br />					<input type = 'submit' name = 'register1' value = 'Register'/><br />				</td><br />			</tr><br />		</table><br />	</form><br />	<?php<br />		}<br />		else<br />		{<br />	?><br />	E-mail:<br />	<?php <br />		echo $_POST['email']; <br />	?><br />	<br /><br />	Name:<br />	<?php <br />		echo $_POST['last_name']; <br />	?><br />	<br /><br />	Password:<br />	<?php <br />		echo $_POST['password']; <br />	?><br />	<?php<br />		}<br />	?><br /></body><br /></html>

Nach dem Login kopieren

初学 PHP　问个问题　在这里　获取
E-mail:
echo $_POST['email'];
?>

Name:

Password:

这些信息时只输出一个没问题
当我输出多个的时候像这个样子的
E-mail:
echo $_POST['email'];
?>

Name:
echo $_POST['last_name'];
?>

Password:
echo $_POST['password'];
?>
他就出错了 - -！！！
总是出现
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Faithfully yours, nginx.
这个东西只输出一个时就可以
各位大神请指教

------解决方案--------------------

<br><title>Register</title><br><br>    <?php <br />    if (!isset($_POST['register1']) <br><font color="#FF8000">------解决方案--------------------</font><br> ( $_POST['register1'] != 'Register'))<br>    {<br>            #echo "test1";<br>    ?><br>    <h1>Registration</h1><br>

Nach dem Login kopieren

E-mail address:
First Name:
Last Name:
PassWord: