求PHP+SQLServer的翻页效果,该怎么处理

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Freigeben： 2016-06-13 12:55:55

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求PHP+SQLServer的翻页效果

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><br />
<html xmlns="http://www.w3.org/1999/xhtml"><br />
<head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><br />
<title>分页实例</title><br />
<style><br />
.page A{ padding:3px 5px; float:left; border:solid #CCCCCC 1px; text-decoration:none; font-size:10px; margin-left:1px; font-family:Verdana;color:#000000;}<br />
.page A.currentpage{ color:#FF0000; border: solid red 1px;}<br />
.page A:hover{ background-color:#CCCCCC;}<br />
</style><br />
</head><br />
<br />
<body><?php<br />
<br />
error_reporting(7);<br />
//初始化翻页链接参数<br />
$page=$_GET["page"]+0;  //思考这里是用强制转换为整数还是用什么方法呢<br />
$page= $page<=0 ? 1 : $page;  //避免$_GET["page"]为负数和0的情况<br />
<br />
//分页尺寸<br />
$page_size=10;<br />
<br />
$serverName = "(local)"; //数据库服务器地址 <br />
$uid = "sa"; //数据库用户名 <br />
$pwd = "ulptfstx"; //数据库密码 <br />
$connectionInfo = array("UID"=>$uid, "PWD"=>$pwd, "Database"=>"MSD"); <br />
$conn = sqlsrv_connect( $serverName, $connectionInfo); <br />
  if( $conn == false) {<br />
	  echo "连接失败！";<br />
	  die( print_r( sqlsrv_errors(), true));<br />
  }<br />
<br />
//计算总行数<br />
$total_records=sqlsrv_num_rows(sqlsrv_query("SELECT MB001 from INVMB"));<br />
<br />
//总页数<br />
$total_page=ceil($total_records/$page_size);  //进一法取整，避免最后一页不满$page_size,   <br />
<br />
$page=$page>$total_page?$total_page:$page;  //避免$_GET["page"]大于总页数<br />
<br />
//翻页链接开始<br />
$page_link="";<br />
if ($total_page>1)<br />
{<br />
	$page_link="<a>一共{$total_page}页</a>";<br />
	$page_link.="<a>当前第{$page}页</a>";<br />
	$page_link.="<a href=?page=1>首页</a>";<br />
	<br />
	if ($page>1){<br />
		//页码大于1的时候，显示上一页翻页链接<br />
		$pre_page=$page-1;<br />
		$page_link.="<a  href='?page=$pre_page'><<</a>";<br />
		}<br />
		//翻页列表<br />
		for ($i=1;$i<=$total_page;$i++)<br />
		{<br />
			if ($i==$page)<br />
			{<br />
				//高亮当前页页码<br />
				$page_link.="<a href='?page=$i' class='currentpage'>$i</a>";<br />
			}<br />
			else<br />
			{<br />
				$page_link.="<a href='?page=$i'>$i</a>";<br />
			}<br />
			}<br />
			//页码小于总页数的时候显示下一页翻页链接<br />
			$next_page=$page+1;<br />
			if($next_page<$total_page)<br />
			{<br />
				$page_link.="<a  href='?page={$next_page}'>>></a>";<br />
			}<br />
			$page_link.="<a  href='?page=$total_page'>最后一页</a>";<br />
		}   <br />
		//输出记录 <br />
<br />
		$offset=($page-1)*$page_size;<br />
		$query=sqlsrv_query("select * from INVMB limit $offset,$page_size")  or die(sqlsrv_error());<br />
		echo "<ul>";<br />
		while ($rs=sqlsrv_fetch_array($query))<br />
		{<br />
			echo "<li>{$rs["0"]}-{$rs["1"]}</li>";<br />
		}<br />
		echo "<ul>";<br />
		echo  "<div class='page'>$page_link</div>";<br />
		<br />
		?><br />
</body><br />
</html>

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这段代码来自 http://topic.csdn.net/u/20120117/11/c2618d08-b88c-4586-8b00-f1938f5c7792.html
怎么把它改成连接SQLServer的，现在运行提示以下错误:

Warning: sqlsrv_query() expects at least 2 parameters, 1 given in D:\Apache server\Apache\htdocs\bbs\demo.php on line 33 <div class="clear">
                 
              
              
        
            </div>

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