Heim > Backend-Entwicklung > Python-Tutorial > python操作数据库之sqlite3打开数据库、删除、修改示例

python操作数据库之sqlite3打开数据库、删除、修改示例

WBOY
Freigeben: 2016-06-16 08:44:54
Original
1353 Leute haben es durchsucht

复制代码 代码如下:

#coding=utf-8
__auther__ = 'xianbao'
import sqlite3
# 打开数据库
def opendata():
        conn = sqlite3.connect("mydb.db")
        cur = conn.execute("""create table if not exists tianjia(
id integer primary key autoincrement, username varchar(128), passworld varchar(128),
address varchar(125), telnum varchar(128))""")
        return cur, conn
#查询全部的信息


def showalldata():
        print "-------------------处理后后的数据-------------------"
        hel = opendata()
        cur = hel[1].cursor()
        cur.execute("select * from tianjia")
        res = cur.fetchall()
        for line in res:
                for h in line:
                        print h,
                print
        cur.close()
#输入信息


def into():
        username1 = str(raw_input("请输入您的用户名:"))
        passworld1 = str(raw_input("请输入您的密码:"))
        address1 = str(raw_input("请输入您的地址:"))
        telnum1 = str(raw_input("请输入您的联系电话:"))
        return username1, passworld1, address1, telnum1
#  (添加)  往数据库中添加内容


def adddata():
        welcome = """-------------------欢迎使用添加数据功能---------------------"""
        print welcome
        person = into()
        hel = opendata()
        hel[1].execute("insert into tianjia(username, passworld, address, telnum)values (?,?,?,?)",
                                        (person[0], person[1], person[2], person[3]))
        hel[1].commit()
        print "-----------------恭喜你数据,添加成功----------------"
        showalldata()
        hel[1].close()
#  (删除)删除数据库中的内容


def deldata():
        welcome = "------------------欢迎您使用删除数据库功能------------------"
        print welcome
        delchoice = raw_input("请输入您想要删除用户的编号:")
        hel = opendata()              # 返回游标conn
        hel[1].execute("delete from tianjia where id ="+delchoice)
        hel[1].commit()
        print "-----------------恭喜你数据,删除成功----------------"
        showalldata()
        hel[1].close()
# (修改)修改数据的内容


def alter():
        welcome = "--------------------欢迎你使用修改数据库功能-----------------"
        print welcome
        changechoice = raw_input("请输入你想要修改的用户的编号:")
        hel =opendata()
        person = into()
        hel[1].execute("update tianjia set username=?, passworld= ?,address=?,telnum=? where id="+changechoice,
                                (person[0], person[1], person[2], person[3]))
        hel[1].commit()
        showalldata()
        hel[1].close()
# 查询数据


def searchdata():
        welcome = "--------------------欢迎你使用查询数据库功能-----------------"
        print welcome
        choice = str(raw_input("请输入你要查询的用户的编号:"))
        hel = opendata()
        cur = hel[1].cursor()
        cur.execute("select * from tianjia where id="+choice)
        hel[1].commit()
        row = cur.fetchone()
        id1 = str(row[0])
        username = str(row[1])
        passworld = str(row[2])
        address = str(row[3])
        telnum = str(row[4])
        print "-------------------恭喜你,你要查找的数据如下---------------------"
        print ("您查询的数据编号是%s" % id1)
        print ("您查询的数据名称是%s" % username)
        print ("您查询的数据密码是%s" % passworld)
        print ("您查询的数据地址是%s" % address)
        print ("您查询的数据电话是%s" % telnum)
        cur.close()
        hel[1].close()
# 是否继续


def contnue1(a):
        choice = raw_input("是否继续?(y or n):")
        if choice == 'y':
                a = 1
        else:
                a = 0
        return a


if __name__ == "__main__":
        flag = 1
        while flag:
                welcome = "---------欢迎使用仙宝数据库通讯录---------"
                print welcome
                choiceshow = """
请选择您的进一步选择:
(添加)往数据库里面添加内容
(删除)删除数据库中内容
(修改)修改书库的内容
(查询)查询数据的内容
选择您想要的进行的操作:
"""
                choice = raw_input(choiceshow)
                if choice == "添加":
                        adddata()
                        contnue1(flag)
                elif choice == "删除":
                        deldata()
                        contnue1(flag)
                elif choice == "修改":
                        alter()
                        contnue1(flag)
                elif choice == "查询":
                        searchdata()
                        contnue1(flag)
                else:
                        print "你输入错误,请重新输入"

Verwandte Etiketten:
Quelle:php.cn
Erklärung dieser Website
Der Inhalt dieses Artikels wird freiwillig von Internetnutzern beigesteuert und das Urheberrecht liegt beim ursprünglichen Autor. Diese Website übernimmt keine entsprechende rechtliche Verantwortung. Wenn Sie Inhalte finden, bei denen der Verdacht eines Plagiats oder einer Rechtsverletzung besteht, wenden Sie sich bitte an admin@php.cn
Beliebte Tutorials
Mehr>
Neueste Downloads
Mehr>
Web-Effekte
Quellcode der Website
Website-Materialien
Frontend-Vorlage