Heim > Backend-Entwicklung > PHP-Tutorial > 菜鸟写的留言板登陆代码各位大神帮我看看,为什么要点击登陆两次才能登陆,为什么要点击两次退出才能退出?

菜鸟写的留言板登陆代码各位大神帮我看看,为什么要点击登陆两次才能登陆,为什么要点击两次退出才能退出?

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Freigeben: 2016-06-23 14:16:15
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PHP 菜鸟写的代码

菜鸟写的留言板登陆代码各位大神帮我看看,为什么要点击登陆两次才能登陆,为什么要点击两次退出才能退出?问题出在哪里,大神帮我看看,先谢谢你了。代码如下:
<?phpinclude("Sql.php");if ($_GET[out]){  setcookie("cookie","out");  echo "<script language=\"javascript\">localhost.href='login.php';</script>";}if ($_POST[id]=='xxx')  {   $pw=md5($_POST[pw]);   if($pw=='e1bfd762321e409cee4ac0b6e841963c')       {         setcookie("cookie","ok");          echo "<script language=\"javascript\">localhost.href='login.php';</script>";       }  }include("Head.php");if ($_COOKIE['cookie']!='ok'){?><SCRIPT language=javascript>function Checklogin()  {     if (myform.id.value=="")     {        alert ("请填写登陆名");        myform.id.focus();        return false;     }      if (myform.pw.value=="")     {        alert ("密码不能为空");        myform.pw.focus();        return false;     }  }</SCRIPT> <form action="" method="post" name="myform" onsubmit="return Checklogin();">  ID:<input type="text" name="id" ><br>  PW:<input type="password" name="pw"> <input type="submit" name="submit" value="登陆" > </form><?}else{?>  <a href='?out=login'>退出</a><?}?>
Nach dem Login kopieren


回复讨论(解决方案)

不知错哪了,望大神指点迷经啊

在纠正了“变量未定义”的警告后,未发现你说的现象
但不能排除是 sql.php 或 head.php 中的问题

贴出你include的文件看下、看是否异样。

贴出你include的文件看下、看是否异样
Sql.php文件代码:

<?php/*CREATE TABLE `message` (  `id` tinyint(1) NOT NULL auto_increment,  `user` varchar(25) NOT NULL,  `title` varchar(50) NOT NULL,  `content` tinytext NOT NULL,  `lastdate` date NOT NULL,  PRIMARY KEY  (`id`)) ENGINE=InnoDB DEFAULT CHARSET=gbk AUTO_INCREMENT=1 ;*/$conn=mysql_connect("localhost","root","") or die ("数据库错误");mysql_select_db("bbs",$conn);mysql_query("set names 'GBK'");  //中文编码function htmtocode($content) {    $content = str_replace("\n","<br>",str_replace(" "," ",$content));       return $content; }//把输入的空格跟换行用str_replace("\n","<br>",str_replace(" "," ",$content))替换成PHP能接受的格式,实现输入什么格式就显示什么格式.?>
Nach dem Login kopieren

Head.php文件代码:
<head><meta http-equiv="Content-Type" content="text/html";charset="gb2312"><title></title><link href="images/css.css" rel="stylesheet" type="text/css"><b><a href="Textbook.php">添加留言</a> | <a href="List.php">浏览留言</a> | <a href="login.php">登陆</a> </b><hr size=1>
Nach dem Login kopieren

Textbook.php文件代码:
<?phpinclude("Sql.php");//if ($_POST['submit'])if (isset($_POST['submit'])) //注一定用(isset($_POST['submit']))因为它是判断 submit的数据提交没有.{     $sql="insert into message(id,user,title,content,lastdate)values('','$_POST[user]','$_POST[title]','$_POST[content]',now())";     mysql_query($sql);     echo "<script language=\"javascript\">alert('添加成功');history.go(-1)</script>";   }include("Head.php");?><SCRIPT language=javascript>function CheckPost(){    if (myform.user.value=="")    {      alert("用户名不能这空,请填写用户名");      myform.user.focus();      return false;    }    if (myform.title.value.length<5)    {      alert("标题不能少于5个字符");      myform.title.focus();      return false;    }    if (myform.content.value.length<8)    {       alert("内容不能少于8个字节");       myform.content.focus();       return false;    }     }</SCRIPT><form action="Textbook.php" method="post" name="myform" onsubmit="return CheckPost();"> <!--注:这里的action="Textbook.php"是定就是当前的文件名-->用户:<input type="text" size="10" name="user"><br>标题:<input type="text" name="title"><br>留言内容:<br><textarea name="content" rows=20 cols=30></textarea><br><input type="submit" name="submit" value="提交留言"></form>
Nach dem Login kopieren

List.php文件代码:
<?include("Sql.php");include("Head.php"); $sql="SELECT * from message order by id desc";  //order by id desc 倒序排列  $query=mysql_query($sql); while($row=mysql_fetch_array($query)){?><table width=500 border="1" align="center" cellpadding="5" cellspacing="2" bgcolor="#add3ef"><tr bgcolor="#eff3ff"><td bgcolor ="eee3ff">ID序列:<?=$row[id]?></td> <td bgcolor ="eff3ff">标题:<?=$row[title]?></td> <td bgcolor ="#aeeffc">用户:<?=$row[user]?></td> <td bgcolor ="#ffffff">内容:<? echo htmtocode($row[content]);?></td></tr></table><? }?>
Nach dem Login kopieren

在纠正了“变量未定义”的警告后,未发现你说的现象
但不能排除是 sql.php 或 head.php 中的问题 
变量未定义是不是指的这里 

setcookie("cookie","out");
改成 setcookie("cookie","out",time()-3600);

-------------
setcookie("cookie","ok");
改成 
setcookie("cookie","ok",time()+3600);

setcookie("cookie","out");
改成 setcookie("cookie","out",time()-3600);

-------------
setcookie("cookie","ok");
改成 
setcookie("cookie","ok",time()+3600); 
 我改了还是要点击两次才能登陆,要点击两次才能退出.
setcookie("cookie","out",time()-3600);
  echo "<script>localhost.href='login.php';</script>";
}
if ($_POST[id]=='xxx')
  {
   $pw=md5($_POST[pw]);
   if($pw=='e1bfd762321e409cee4ac0b6e841963c')
       {
         setcookie("cookie","ok",time()+3600);
          echo "<script>localhost.href='login.php';</script>";
       }
  }

localhost.href='login.php';

不是应该是 location.href=么

所有的localhost都应该是location

Quelle:php.cn
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