Ich habe kürzlich C++ Primer Plus gelesen und finde, dass das Kapitel über Funktionen und Zeiger schwieriger ist.
Aus C++ Primer Plus: Kapitel 7 Funktion: C++-Programmiermodule
1. Wie deklariere ich einen Funktionszeiger?
ähnelt einem Funktionsprototyp: Sie müssen einen Zeiger deklarieren, der auf den Rückgabewert und die Parameterliste der Funktion
double pam(int); //参数为int 类型,返回值为double 类型的函数 double (*pf);(int) //指向参数为int类型,返回值为double 类型的指针 pf = pam; //函数名代表了函数的地址 double x = pam(4); //函数名调用 double x = (*pf)(4); //指针调用 double x = pf(4); //C++也允许将指针名当作函数名使用
<🎜 zeigt >
2. C++ 11 Automatische Typinferenz<br/>
const double * f1(const double *, int); const double * (*p1)(const double *, int); //p1 poitns to f1 auto p2 = f1; //C++11 automatic type deduction,p2 points to f1 as well
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//前面函数为double *类型,cout第一部分返回double指针,第二部分返回double指针指向的值 cout<<(*p1)(av,3)<<":"<<*(*p1)(av,3)<<endl; //和上面的cout一样只不过是使用函数指针名来调用函数 cout<<p2(av,3)<<":"<<*p2(av,3)<<endl;
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const double *(*pa[3]) (const double *,int) = {f1,f2,f3}; //创建函数指针数组 //通过指针调用函数,得到返回的指针 const double *px = pa[0](av,3); //call by pointer as if it were a function name const double *py = (*pa[0])(av,3); //正常调用 //得到函数返回指针指向的值 double x = *pa[0](av,3); double x = *(*pa[0])(av,3);
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*pd[3] //an array of 3 pointers (*pd)[3] //a pointer to an array of three elements
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//arfupt.cpp -- an array of function pointers #include<iostream> //various notations,same signatures const double *f1(const double ar[],int n); const double *f2(const double [],int); const double *f3(const double *,int); int main() { using namespace std; double av[3] = {1112.3,1542.6,2227.9}; //pointer to a function const double *(*p1)(const double *,int) = f1; auto p2 = f2;//C++ 11 utomatic type deduction //pre-C++11 can use the following code instead //const double *(*p2)(const double *,int) = f2; cout<<"Using pointers to functions:\n"; cout<<"Address Value\n"; cout<<(*p1)(av,3)<<":"<<*(*p1)(av,3)<<endl; cout<<p2(av,3)<<":"<<*p2(av,3)<<endl; //pa an array of pointers //auto doesn't work with list initialization const double *(*pa[3])(const double *,int) = {f1,f2,f3}; //pb a pointer to first element of pa auto pb = pa; // pre-C++11 can use the following code instead // const double *(**pb)(const double *, int) = pa; cout<<"\nUsing an array of pointers to functions:\n"; cout<<"Address Value\n"; for(int i = 0;i < 3; i++) cout<<pa[i](av,3)<<":"<<*pa[i](av,3)<<endl; cout<<"\nUsing a pointer to a pointer to a function:\n"; cout<<"Address Value\n"; for(int i = 0;i < 3; i++) cout<<pb[i](av,3)<<":"<<*pb[i](av,3)<<endl; //what about a pointer to an array of function pointers cout<<"\nUsing pointers to an array of pointers:\n"; cout<<"Address Value\n"; //easy way to declare pc auto pc = &pa; // pre-C++11 can use the following code instead // const double *(*(*pc)[3])(const double *, int) = &pa; cout<<(*pc)[0](av,3)<<":"<<*(*pc)[0](av,3)<<endl; //hard way to declare pd const double *(*(*pd)[3])(const double *,int) = &pa; //store return value in pdb const double *pdb = (*pd)[1](av,3); cout<<pdb<<":"<<*pdb<<endl; //alternative notation cout<<(*(pd)[2])(av,3)<<":"<<*(*(*pd)[2])(av,3)<<endl; } const double * f1(const double * ar, int n) { return ar; } const double * f2(const double ar[], int n) { return ar+1; } const double * f3(const double ar[], int n) { return ar+2; }
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