🎜9. Verwenden Sie die Concat-Funktion anstelle von „+“🎜🎜 concat(last_name,first_name)🎜🎜🎜🎜🎜🎜Versuchen Sie nach dem Erlernen der Grundabfrage, die folgenden Übungen durchzuführen🎜 🎜🎜Antwort: 🎜 1.Richtig🎜 2.Richtig🎜 3.Anführungszeichen sollten im Englischen verwendet werden🎜 4.DESC-Abteilungen;;SELECT * FROM-Abteilungen;🎜 5. SELECT CONCAT(first_name,',',last_name,',',IFNULL(email,0)) AS "out_put" FROM states;🎜🎜🎜🎜🎜2. Bedingte Abfrage🎜🎜🎜Syntax: Abfrageliste aus Tabellenname auswählen, wobei Filterbedingungen gelten;🎜🎜Ausführungsreihenfolge: von > auswählen (zuerst die Tabelle suchen, dann mit der Filterung beginnen und schließlich abfragen)🎜🎜 Kategorie : 🎜🎜(1) Nach bedingtem Operator filtern🎜【分组函数】/*
SUM 求和
AVG 平均值
MAX 最大值
MIN 最小值
COUNT 计算个数
*/# 综合使用SELECT SUM(salary) "和",AVG(salary) "平均数",MAX(salary) "最大值",MIN(salary) "最小值",COUNT(salary) "总个数" FROM employees;/*
分组函数的特点:
1.sum、avg一般用于处理数值型；max、min、count可以处理任何类型
2.分组函数都忽略null值,都可以和distinct搭配去重
3.和分组函数一同查询的字段要求是group by后的字段
4.count函数经常用来统计行数,使用count(*)或count(1)或count(常量)
效率问题:
MYISAM存储引擎下,count(*)效率高
INNODB存储引擎下,count(*)和count(1)效率差不多,但比count(字段)要高
*/ Nach dem Login kopieren Nach dem Login kopieren # 1.查询每个工种的最高工资SELECT MAX(salary) "最高工资",job_id "工种" FROM employees GROUP BY job_id;# 2.查询每个位置上的部门个数SELECT COUNT(*) "部门个数",location_id "位置id" FROM departments GROUP BY location_id;# 3.查询邮箱中包含a字符的,每个部门的平均工资SELECT AVG(salary) "平均工资",department_id "部门id" FROM employees WHERE email LIKE '%a%' GROUP BY department_id;# 4.查询每个领导手下的有奖金的员工的最高工资SELECT MAX(salary) "最高工资",manager_id "领导编号" FROM employees WHERE NOT ISNULL(commission_pct) GROUP BY manager_id;# 5.查询哪个部门的员工个数>2# 思路:查询每个部门的个数,再根据结果哪个部门的员工个数>2SELECT COUNT(*),department_id FROM employees GROUP BY department_id HAVING COUNT(*)>2;# 6.查询每个工种有奖金的员工的最高工资>12000的工种编号和最高工资SELECT MAX(salary) "最高工资",job_id "工种" FROM employees WHERE NOT ISNULL(commission_pct) GROUP BY job_id HAVING MAX(salary)>12000;# 7.查询领导编号>102的每个领导手下员工的最低工资>5000的领导编号是哪个,以及其最低工资SELECT MIN(salary) "最低工资",manager_id "领导编号" FROM employees WHERE manager_id>102 GROUP BY manager_id HAVING MIN(salary)>5000;# 8.按员工姓名的长度分组,查询每一组的员工个数,筛选员工个数>5的有哪些SELECT COUNT(*) "员工个数",LENGTH(last_name) "姓名长度" FROM employees GROUP BY LENGTH (last_name) HAVING COUNT(*)>5;# 9.查询每个部门每个工种的员工的平均工资SELECT AVG(salary) "平均工资",department_id "部门",job_id "工种" FROM employees GROUP BY department_id,job_id; # 10.查询每个部门每个工种的员工的平均工资,并按平均工资的高低显示SELECT AVG(salary) "平均工资",department_id "部门",job_id "工种" FROM employees GROUP BY department_id,job_id ORDER BY AVG(salary) DESC; Nach dem Login kopieren Nach dem Login kopieren 【sql92标准】# 1.等值连接# 查询女神名和对应的男朋友名# SELECT NAME,boyName FROM boys,beauty WHERE beauty.boyfriend_id=boys.id;# 1.查询员工名和对应的部门名SELECT last_name "员工名",department_name "部门名" FROM employees,departments
WHERE employees.department_id=departments.department_id;# 2.查询员工名、工种号、工种名SELECT last_name,e.job_id,job_title FROM employees e,jobs j WHERE e.`job_id`=j.`job_id`;# 3.查询有奖金的员工名、部门名SELECT last_name,department_name,commission_pct FROM employees e,departments d
WHERE e.`department_id`=d.`department_id` AND e.`commission_pct` IS NOT NULL;# 等值连接+筛选# 4.查询城市中第二个字符为o的部门名和城市名SELECT department_name "部门名",city "城市名" FROM departments d,locations l
WHERE d.`location_id`=l.`location_id` AND city LIKE '_o%'; # 等值连接+分组# 5.查询每个城市的部门个数SELECT COUNT(*) "部门个数",city "城市" FROM departments d,locations l
WHERE d.`location_id`=l.`location_id` GROUP BY city;# 6.查询有奖金的每个部门的部门名、部门的领导编号、该部门最低工资SELECT department_name,d.manager_id,MIN(salary) FROM departments d,employees e
WHERE d.`department_id`=e.`department_id` AND commission_pct IS NOT NULL GROUP BY department_name,d.manager_id;# 7.查询每个工种的工种名、员工的个数并按员工的个数降序SELECT job_title,COUNT(*) FROM employees e,jobs j WHERE e.`job_id`=j.`job_id` GOUP BY job_title ORDER BY COUNT(*) DESC;# 8.支持三表连接# 查询员工名、部门名、所在的城市SELECT last_name,department_name,city FROM employees e,departments d,locations l
WHERE e.`department_id`=d.`department_id` AND d.`location_id`=l.`location_id`;# (2)非等值连接/*
先执行下面的语句,在myemployees数据库中创建新的job_grades表。
CREATE TABLE job_grades
(grade_level VARCHAR(3),
lowest_sal INT,
highest_sal INT);
INSERT INTO job_grades
VALUES ('A', 1000, 2999);
INSERT INTO job_grades
VALUES ('B', 3000, 5999);
INSERT INTO job_grades
VALUES('C', 6000, 9999);
INSERT INTO job_grades
VALUES('D', 10000, 14999);
INSERT INTO job_grades
VALUES('E', 15000, 24999);
INSERT INTO job_grades
VALUES('F', 25000, 40000);
*/# 1.查询员工的工资和工资级别SELECT salary,grade_level FROM employees e,job_grades j WHERE salary BETWEEN j.`lowest_sal` AND j.`highest_sal`;# (3)自连接# 1.查询员工名和其上级的名称.SELECT e.employee_id "员工id",e.last_name "员工姓名",m.employee_id "经理id",m.last_name "经理姓名" FROM employees e,employees m WHERE e.`manager_id`=m.`employee_id`;Nach dem Login kopieren Nach dem Login kopieren 【sql99标准】# (1)等值连接# 1.查询员工名,部门名SELECT last_name,department_name
FROM employees eINNER JOIN departments dON e.department_id=d.department_id;# 2.查询名字中包含e的员工名和工种名(添加筛选)SELECT last_name,job_titleFROM employees eINNER JOIN jobs jON e.job_id=j.job_idWHERE last_name LIKE '%e%' OR job_title LIKE '%e%';# 3.查询部门个数>3的城市名和部门个数(分组+筛选)SELECT city,COUNT(*) "部门个数"FROM departments dINNER JOIN locations lON d.location_id=l.location_idGROUP BY cityHAVING COUNT(*)>3;# 4.查询哪个部门的部门员工个数>3的部门名和员工个数,并按个数降序(排序)SELECT department_name "部门名",COUNT(*) "员工个数"FROM departments dINNER JOIN employees eON d.department_id=e.department_idGROUP BY department_nameHAVING COUNT(*)>3ORDER BY COUNT(*) DESC;# 5.查询员工名、部门名、工种名、并按部门名排序SELECT last_name "员工名",department_name "部门名",job_title "工种名"FROM employees eINNER JOIN departments d ON d.department_id=e.department_idINNER JOIN jobs j ON e.job_id=j.job_idORDER BY department_name ;# (2)非等值连接# 查询员工工资级别SELECT salary,grade_levelFROM employees eJOIN job_grades j ON e.`salary` BETWEEN j.lowest_sal AND j.highest_sal;# 查询每个工资级别的个数>20的个数,并且按照工资级别降序排列SELECT COUNT(*),grade_levelFROM employees eJOIN job_grades j ON e.`salary` BETWEEN j.lowest_sal AND j.highest_salGROUP BY grade_levelHAVING COUNT(*)>20ORDER BY grade_level DESC;# (3)自连接# 查询员工的名字、上级的名字SELECT e1.last_name "员工名",e2.last_name "上级名"FROM employees e1JOIN employees e2 ON e1.manager_id=e2.employee_id;--------------------------------------------------------------------------------------------------------------# 二、外连接# 1.查询男朋友不在男神表的女神名# 左外连接SELECT NAME
FROM beauty LEFT OUTER JOIN boys ON beauty.boyfriend_id=boys.idWHERE boys.id IS NULL;# 右外连接SELECT NAMEFROM boys RIGHT OUTER JOIN beauty ON beauty.boyfriend_id=boys.idWHERE boys.id IS NULL;# 2.查询没有员工的部门SELECT d.department_name,e.employee_idFROM departments d LEFT JOIN employees e ON d.department_id=e.department_idWHERE e.manager_id IS NULL;SELECT * FROM employees WHERE employee_id=100;# 3.全外连接(不支持)# 全外连接就是就并集USE girls;SELECT b.*,bo.*FROM beauty bFULL JOIN boys boON b.boyfriend_id=bo.id;# 三.交叉连接# 使用99标准实现的笛卡尔乘积,使用cross代替了92中的,SELECT b.*,bo.*FROM beauty bCROSS JOIN boys bo Nach dem Login kopieren Nach dem Login kopieren
| Zusammenfassung der bedingten Abfrage |
Erklärung | 🎜
| 🎜(1) Filtern nach bedingtem Operator🎜🎜 |
> )🎜🎜 |
| 🎜(2) Nach logischem Ausdruck filtern🎜🎜 |
&& || !oder und oder nicht🎜🎜 |
| 🎜(3) Fuzzy-Abfrage🎜🎜 |
Schlüsselwörter: like, between...and, in, is null🎜🎜 🎜🎜学完了条件查询，尝试完成下面的练习题
答案：
一、SELECT salary,last_name FROM employees WHERE commission_pct IS NULL AND salary <br> 二、<code>SELECT * FROM employees WHERE job_id 'IT' OR salary=12000;
三、DESC departments;
四、SELECT DISTINCT location_id FROM departments;
五、不一定,考虑字段有null的情况.
三、排序查询
语法：select 查询列表 from 表 where 筛选条件 order by 排序列表 asc|desc
特点：
- 1.asc代表升序，esc代表降序，不写默认是升序。
- 2.order by子句支持单个字段、多个字段、表达式、函数、别名
执行顺序：from > where > select > order by (order by一般放在查询语句的最后面，limit子句除外(后面会讲到))
【排序查询】# 1.查询员工信息,要求工资从高到低排序SELECT * FROM employees ORDER BY salary DESC;# 2.查询部门编号>=90的员工信息,按入职时间的先后进行排序【添加筛选条件】SELECT * FROM employees WHERE department_id>=90 ORDER BY hiredate ASC;# 3.按照年薪的高低显示员工的信息和年薪【添加表达式排序】SELECT * ,salary*12*(1+IFNULL(commission_pct,0)) AS 年薪 FROM employees ORDER BY salary*12*(1+IFNULL(commission_pct,0)) DESC;SELECT * ,salary*12*(1+IFNULL(commission_pct,0)) AS 年薪 FROM employees ORDER BY 年薪 DESC; # ORDER BY后支持别名# 4.按照姓名的长度,显示员工的姓名和工资【按函数排序】SELECT LENGTH(last_name) AS 字节长度, last_name,salary FROM employees ORDER BY 字节长度 DESC;# 5.查询员工信息,先按工资升序,再按员工编号降序SELECT * FROM employees ORDER BY salary ASC ,employee_id DESC; Nach dem Login kopieren Nach dem Login kopieren 学完了排序查询，尝试完成下面的练习题
答案：
1、SELECT last_name,department_id,salary*12*(1+IFNULL(commission_pct,0)) AS 年薪 FROM employees ORDER BY 年薪 DESC,last_name ASC;
2、SELECT last_name,salary FROM employees WHERE salary NOT BETWEEN 8000 AND 17000 ORDER BY salary DESC;
3、SELECT * FROM employees WHERE email LIKE '%e%' ORDER BY LENGTH(email) DESC,department_id ASC;
| 排序查询总结 |
说明 |
| 升序 |
order by asc |
| 降序 |
order by desc |
4. Allgemeine Funktionen
Aufrufssyntax: Funktionsnamen (aktuelle Parameterliste) aus Tabelle auswählen;select 函数名(实参列表) from 表;
概念：类似于Java中的方法，将一组逻辑语句封装在方法体中，对外暴露接口。
好处：
1.隐藏了实现细节
2.提高代码重用性
分类：分为单行函数和分组函数。其中单行函数又分为：字符函数、数学函数、日期函数、系统函数、流程控制函数。；分组函数用来做统计功能，又称为统计函数、聚合函数、组函数。
| 单行函数 |
说明 |
| (1)字符函数 |
参数类型为字符型 |
| 获取参数值的字节个数 |
select length('字符串') |
| 拼接 |
concat(字段1,字段2) |
| 大小写转换 |
upper、lower |
| 截取 |
substr(index,end) |
| 查找 |
instr(主串,子串) |
| 清除两边空格 |
trim(a from'aaaa字符串1aa') |
| 左右填充 |
lpad('字符串1',左填充个数n,填充字符'a')、lpad('字符串1',右填充个数n,填充字符'a')
|
| 替换 |
replace('字符串1','被更换的字符串','新的字符串') |
| (2)数学函数 |
参数类型为数值 |
| 四舍五入 |
round(小数,保留位数) |
| 截取 |
truncate(小数,保留位数) |
| 向上取整 |
ceil(被向上取整的数值) |
| 向下取整 |
floor(被向下取整的数值) |
| 取余 |
mod(n,m);结果的正负和被取余数n相同 |
| 随机数 |
rand();返回0-1之间的小数 |
| (3)日期函数 |
参数为日期 |
| 返回当前完整日期 |
select now(); |
| 返回当前年月日 |
select curdate(); |
| 返回当前时分秒 |
select curtime(); |
| 截取指定部分 |
select YEAR(now()) as 年,MONTH(now()) as 月,DAY(now()) as 日; |
| 字符串→日期 |
STR_TO_DATE('2020-7-7','%Y-%m-%d') |
| 日期→字符串 |
DATE_FORMAT(NOW(),'%Y年%m月%d日') |
| 返回两个日期相差的天数 |
datediff(日期1,日期2) |
| (4)系统函数 |
系统自带 |
| 查看当前版本 |
select version(); |
| 查看当前数据库 |
select database(); |
| 查看当前用户 |
select user(); |
| 自动加密 |
password('字符');或md5('字符'); |
| (5)流程控制函数 |
类比Java |
| if |
if(奖金 IS NULL,'没奖金','有奖金') |
 |
 |
| 分组函数 |
说明 |
| sum |
求和 |
| avg |
平均值 |
| max |
最大值 |
| min |
最小值 |
| count |
计算个数 | Konzept: Ähnlich wie bei Methoden in Java ist eine Reihe logischer Anweisungen in der Methode gekapselt body ist die Schnittstelle der Außenwelt ausgesetzt.
Vorteile:
1. Versteckte Implementierungsdetails
2. Verbessern Sie die Wiederverwendbarkeit des Codes 🎜Klassifizierung: Unterteilt in einzeilige Funktionen und gruppierte Funktionen. Unter diesen sind einzeilige Funktionen unterteilt in: Zeichenfunktionen, mathematische Funktionen, Datumsfunktionen, Systemfunktionen und Prozesssteuerungsfunktionen. ;Gruppenfunktion wird für statistische Funktionen verwendet, die auch als statistische Funktionen, Aggregatfunktionen und Gruppenfunktionen bezeichnet werden. 🎜
| Einzelzeilenfunktion |
Beschreibung | 🎜
| 🎜( 1) Zeichenfunktion🎜🎜 |
🎜Der Parametertyp ist Zeichentyp🎜🎜🎜 |
| Ermitteln Sie die Anzahl der Bytes des Parameterwerts🎜 |
wählen Sie die Länge('string') code>🎜 🎜<tr>
<td>Spleißen🎜</td>
<td>
<code>concat(Feld 1, Feld 2)🎜🎜 |
| Fallkonvertierung🎜 |
oben, unten code>🎜🎜 |
| Intercept 🎜 |
substr(index,end)🎜🎜 |
| Find 🎜 |
instr( Hauptzeichenfolge, Unterzeichenfolge)🎜🎜 |
| Leerzeichen auf beiden Seiten löschen🎜 |
trim(a from'aaaa string 1aa')🎜🎜 |
Links und rechts auffüllen🎜
lpad('String 1', linke Auffüllnummer n, Auffüllzeichen 'a'), lpad('String 1', rechte Auffüllnummer n , Füllzeichen 'a')🎜🎜 |
| Replace🎜 |
replace('String 1','Replaced string','New string')🎜🎜 |
| 🎜(2) Mathematische Funktion🎜🎜 |
🎜Parametertyp ist numerischer Wert🎜🎜🎜 |
| Rundung🎜 |
round(dezimal, reservierte Ziffern) 🎜🎜 |
| Intercept 🎜 |
truncate(decimal, reservierte Ziffern)🎜🎜 |
| Aufrunden🎜 |
ceil (der Wert, der wird aufgerundet)🎜🎜 |
| abgerundet🎜 |
Untergrenze (der Wert, der abgerundet wird)🎜🎜 |
| Rest 🎜 |
mod(n,m); das Vorzeichen des Ergebnisses ist das gleiche wie der Rest n🎜🎜 |
| Zufallszahl 🎜 |
rand(); Dezimal zwischen 0-1🎜🎜 |
| 🎜(3) Datumsfunktion🎜🎜 |
🎜Der Parameter ist das Datum🎜🎜🎜 |
Gibt das aktuelle vollständige Datum zurück🎜select now();🎜🎜 |
| Gibt das aktuelle Jahr, den aktuellen Monat und den aktuellen Tag zurück🎜 |
select curdate();🎜🎜 |
| Gibt die aktuelle Stunde, Minute und Sekunde zurück🎜 |
select curtime();🎜🎜 |
| Den angegebenen Teil abfangen🎜 |
select YEAR( now() ) als Jahr, MONTH(now()) als Monat, DAY(now()) als Tag;🎜🎜 |
| String→Date🎜 |
STR_TO_DATE(' 2020- 7-7','%Y-%m-%d')🎜🎜 |
| Date→String🎜 |
DATE_FORMAT(NOW(),'%YYear% m Monat %d Tag')🎜🎜 |
| Gibt die Anzahl der Tage Differenz zwischen zwei Daten zurück🎜 |
datediff(date1, date2)🎜🎜 |
| 🎜(4) Systemfunktion🎜🎜 |
🎜Das System ist im Lieferumfang enthalten🎜🎜🎜 |
| Aktuelle Version anzeigen🎜 |
Version auswählen();🎜 🎜 |
| Aktuelle Datenbank anzeigen🎜 |
select Database();🎜🎜 |
| Aktuellen Benutzer anzeigen🎜 |
select user() ; 🎜🎜 |
| Automatische Verschlüsselung🎜 |
password('character'); oder md5('character');🎜🎜 |
| 🎜 (5) Prozesssteuerungsfunktion 🎜🎜 |
🎜Analogie Java🎜🎜🎜 |
| if🎜 |
if(Bonus IS NULL,'No Bonus','With Bonus')🎜🎜 |
|
🎜 |
🎜🎜🎜🎜
| Gruppenfunktion |
Beschreibung | 🎜
| 🎜sum🎜🎜 |
Summe🎜🎜<tr>
<td>🎜avg🎜🎜</td>
<td>
<code>Durchschnitt🎜🎜 |
| 🎜max🎜🎜 |
Maximalwert🎜🎜<tr>
<td>🎜min🎜🎜</td>
<td>
<code>Mindestwert🎜🎜 |
| 🎜count🎜🎜 |
Zählerzahl 🎜🎜🎜🎜【单行函数】# (1)字符函数-[参数类型为字符型]# 1.length 获取参数值的字节个数SELECT LENGTH('john');SELECT LENGTH('张三丰');SHOW VARIABLES LIKE '%char%' # 查看字符集# 2.concat拼接字符串SELECT CONCAT(last_name,'_',first_name) 姓名 from employees;# 3.upper、lower 大小写转换SELECT UPPER('tom');SELECT LOWER('TOM')# 将姓变大写,名变小写,然后拼接SELECT CONCAT(UPPER(last_name),LOWER(first_name))姓名 FROM employees;# 4.substr 拼接函数# mysql中的索引从1开始SELECT SUBSTR('若负平生意,何名作莫愁',7) AS out_put;SELECT SUBSTR('若负平生意,何名作莫愁',1,3) AS out_put;# 案例:姓名中首字符大写,其他字符小写,用_拼接并显示出来SELECT CONCAT(UPPER(SUBSTR(last_name,1,1)),'_',LOWER(SUBSTR(last_name,2))) oup_put FROM employees; # 5.instr 字符查找函数# 返回子串在主串中的起始索引,没有返回零SELECT INSTR('凡尘阿凉','阿凉') AS out_put;# 6.trim 清除空格函数# 将字符两边的空格移除SELECT LENGTH(TRIM(' 凡尘 ')) AS out_put;SELECT TRIM('a' FROM 'aaaaaa凡aaa尘aaaa') AS out_put;# 7.lpad 左填充函数# 用指定的字符实现左填充指定长度SELECT LPAD('凡尘',10,'*') AS out_put;# 8.rpad 右填充函数# 用指定的字符实现右填充指定长度SELECT RPAD('凡尘',10,'*') AS out_put;# 9.replace 替换函数SELECT REPLACE('我的偶像是鲁迅','鲁迅','周冬雨') AS oup_put;---------------------------------------------------------------------------------------------------------# (2)数学函数-[参数类型为数值]# 1.round 四舍五入函数SELECT ROUND(1.65);SELECT ROUND(1.567,2);# 2.ceil 向上取整函数# 返回>=该参数的最小整数SELECT CEIL(1.00);# 3.floor 向下取整函数# 返回5,'大于','小于');SELECT last_name,commission_pct, IF(commission_pct IS NULL,'没奖金','有奖金') AS out_put FROM employees;# 2.MySQL Essence One: DQL-Datenabfrageanweisung函数/*
方式一：类似于Java中的switch-MySQL Essence One: DQL-Datenabfrageanweisung：
案例:查询员工工资,要求
部门号=30,显示的工资为1.1倍
部门号=40,显示的工资为1.2倍
部门号=50,显示的工资为1.3倍
其他部门,显示的工资为原工资
*/SELECT salary 原始工资,department_id,CASE department_idWHEN 30 THEN salary*1.1WHEN 40 THEN salary*1.2WHEN 50 THEN salary*1.3ELSE salaryEND AS 新工资FROM employees;/*
方式二：类似于Java中的多重if:
案例:查询员工的工资情况
工资>20000,显示A级别
工资>15000,显示B级别
工资>10000,显示C级别
否则,显示D级别
*/SELECT salary,CASEWHEN salary>20000 THEN 'A'WHEN salary>15000 THEN 'B'WHEN salary>10000 THEN 'C'ELSE 'D'END AS 工资级别FROM employees;Nach dem Login kopieren Nach dem Login kopieren 【分组函数】/*
SUM 求和
AVG 平均值
MAX 最大值
MIN 最小值
COUNT 计算个数
*/# 综合使用SELECT SUM(salary) "和",AVG(salary) "平均数",MAX(salary) "最大值",MIN(salary) "最小值",COUNT(salary) "总个数" FROM employees;/*
分组函数的特点:
1.sum、avg一般用于处理数值型；max、min、count可以处理任何类型
2.分组函数都忽略null值,都可以和distinct搭配去重
3.和分组函数一同查询的字段要求是group by后的字段
4.count函数经常用来统计行数,使用count(*)或count(1)或count(常量)
效率问题:
MYISAM存储引擎下,count(*)效率高
INNODB存储引擎下,count(*)和count(1)效率差不多,但比count(字段)要高
*/ Nach dem Login kopieren Nach dem Login kopieren 学完了单行函数，尝试完成下面的练习题
答案:
1、SELECT NOW();
2、SELECT employee_id,last_name,salary*1.2 "new salary" FROM employees;
3、SELECT LENGTH(last_name) "长度",SUBSTR(last_name,1) "首字符",last_name FROM employees ORDER BY 首字符;
4、SELECT CONCAT(last_name,' earns '),salary,' monthly but wants ',salary*3 AS "Dream Salary" FROM employees WHERE salary=24000;
5、
SELECT last_name,job_id AS job,
CASE job_id
WHEN ‘AD_PRES’ THEN ‘A’
WHEN ‘ST_MAN’ THEN ‘B’
WHEN ‘IT_PROG’ THEN ‘C’
WHEN ‘SA_PRE’ THEN ‘D’
WHEN ‘ST_CLERK’ THEN ‘E’
END AS “Grade”
FROM employees
WHERE job_id =“AD_PRES”;
学完了分组函数，尝试完成下面的练习题：
答案：
1.SELECT ROUND(MAX(salary),2) "最大值",ROUND(MIN(salary),2) "最小值",ROUND(AVG(salary),2) "平均值",ROUND(SUM(salary),2) "总和" FROM employees;
2.SELECT DATEDIFF(MAX(hiredate),MIN(hiredate)) "DIFFERNCE" FROM employees;
3.SELECT COUNT(*) AS "员工个数" FROM employees WHERE department_id=90;
五、分组查询
语法:
select 分组函数,查询列表(要求出现在group by的后面)
from 表
【where 筛选条件】
group by 分组的列表
【having 分组后的筛选】
【order by 子句】
执行顺序：from > where > group by > having > select > order by
| 分类 |
筛选源 |
位置 |
关键字 |
| 分组前筛选 |
原始表 |
group by |
where |
| 分组后筛选 |
分组后的结果集 |
group by |
having |
注意：
1.查询列表必须是分组函数和group by后出现的字段。
2.分组函数做条件一定放在having子句中。
3.能用分组前筛选的优先使用分组前筛选。
4.group by子句支持单个字段分组、多个字段分组(多个字段之间用逗号隔开，没有顺序要求)、表达式或函数。
5.可以添加排序(排序放在整个分组查询最后)
6.一般不在group by和having后使用别名。
# 1.查询每个工种的最高工资SELECT MAX(salary) "最高工资",job_id "工种" FROM employees GROUP BY job_id;# 2.查询每个位置上的部门个数SELECT COUNT(*) "部门个数",location_id "位置id" FROM departments GROUP BY location_id;# 3.查询邮箱中包含a字符的,每个部门的平均工资SELECT AVG(salary) "平均工资",department_id "部门id" FROM employees WHERE email LIKE '%a%' GROUP BY department_id;# 4.查询每个领导手下的有奖金的员工的最高工资SELECT MAX(salary) "最高工资",manager_id "领导编号" FROM employees WHERE NOT ISNULL(commission_pct) GROUP BY manager_id;# 5.查询哪个部门的员工个数>2# 思路:查询每个部门的个数,再根据结果哪个部门的员工个数>2SELECT COUNT(*),department_id FROM employees GROUP BY department_id HAVING COUNT(*)>2;# 6.查询每个工种有奖金的员工的最高工资>12000的工种编号和最高工资SELECT MAX(salary) "最高工资",job_id "工种" FROM employees WHERE NOT ISNULL(commission_pct) GROUP BY job_id HAVING MAX(salary)>12000;# 7.查询领导编号>102的每个领导手下员工的最低工资>5000的领导编号是哪个,以及其最低工资SELECT MIN(salary) "最低工资",manager_id "领导编号" FROM employees WHERE manager_id>102 GROUP BY manager_id HAVING MIN(salary)>5000;# 8.按员工姓名的长度分组,查询每一组的员工个数,筛选员工个数>5的有哪些SELECT COUNT(*) "员工个数",LENGTH(last_name) "姓名长度" FROM employees GROUP BY LENGTH (last_name) HAVING COUNT(*)>5;# 9.查询每个部门每个工种的员工的平均工资SELECT AVG(salary) "平均工资",department_id "部门",job_id "工种" FROM employees GROUP BY department_id,job_id; # 10.查询每个部门每个工种的员工的平均工资,并按平均工资的高低显示SELECT AVG(salary) "平均工资",department_id "部门",job_id "工种" FROM employees GROUP BY department_id,job_id ORDER BY AVG(salary) DESC; Nach dem Login kopieren Nach dem Login kopieren 学完了分组查询，尝试完成下面的练习题
答案：
1、SELECT MAX(salary),MIN(salary),AVG(salary),SUM(salary),job_id FROM employees GROUP BY job_id ORDER BY job_id ASC;
2、SELECT MAX(salary)-MIN(salary) "DIFFERENCE" FROM employees;
3、SELECT MIN(salary) ,manager_id FROM employees WHERE NOT ISNULL(manager_id) GROUP BY manager_id HAVING MIN(salary)>=6000;
4、SELECT department_id,COUNT(*),AVG(salary) FROM employees GROUP BY department_name ORDER BY AVG(salary) DESC;
5、SELECT COUNT(*) "个数",job_id FROM employees GROUP BY job_id;
六、连接查询
概念：查询的字段来自多个表。
分类：安装年代可以分为sql92和sq99，按照功能分为内连接(交集)、外连接(一个表中有,另一个表中没有)、交叉连接；其中sql92仅支持内连接，sql99除全外连接其他全都支持。
注意：
1.如果为表起了别名,则查询的字段就不能使用原来的表名去限定。
2.当涉及到多表查询时,为表起别名可以有效提高语句简洁度,方便区分多个重名的字段。
连接查询分为下面三类：
(1)内连接inner
(2)外连接
- 左外连接
left outer
- 右外连接
right outer
- 全外连接
full outer
(3)交叉连接cross
【sql92标准】# 1.等值连接# 查询女神名和对应的男朋友名# SELECT NAME,boyName FROM boys,beauty WHERE beauty.boyfriend_id=boys.id;# 1.查询员工名和对应的部门名SELECT last_name "员工名",department_name "部门名" FROM employees,departments
WHERE employees.department_id=departments.department_id;# 2.查询员工名、工种号、工种名SELECT last_name,e.job_id,job_title FROM employees e,jobs j WHERE e.`job_id`=j.`job_id`;# 3.查询有奖金的员工名、部门名SELECT last_name,department_name,commission_pct FROM employees e,departments d
WHERE e.`department_id`=d.`department_id` AND e.`commission_pct` IS NOT NULL;# 等值连接+筛选# 4.查询城市中第二个字符为o的部门名和城市名SELECT department_name "部门名",city "城市名" FROM departments d,locations l
WHERE d.`location_id`=l.`location_id` AND city LIKE '_o%'; # 等值连接+分组# 5.查询每个城市的部门个数SELECT COUNT(*) "部门个数",city "城市" FROM departments d,locations l
WHERE d.`location_id`=l.`location_id` GROUP BY city;# 6.查询有奖金的每个部门的部门名、部门的领导编号、该部门最低工资SELECT department_name,d.manager_id,MIN(salary) FROM departments d,employees e
WHERE d.`department_id`=e.`department_id` AND commission_pct IS NOT NULL GROUP BY department_name,d.manager_id;# 7.查询每个工种的工种名、员工的个数并按员工的个数降序SELECT job_title,COUNT(*) FROM employees e,jobs j WHERE e.`job_id`=j.`job_id` GOUP BY job_title ORDER BY COUNT(*) DESC;# 8.支持三表连接# 查询员工名、部门名、所在的城市SELECT last_name,department_name,city FROM employees e,departments d,locations l
WHERE e.`department_id`=d.`department_id` AND d.`location_id`=l.`location_id`;# (2)非等值连接/*
先执行下面的语句,在myemployees数据库中创建新的job_grades表。
CREATE TABLE job_grades
(grade_level VARCHAR(3),
lowest_sal INT,
highest_sal INT);
INSERT INTO job_grades
VALUES ('A', 1000, 2999);
INSERT INTO job_grades
VALUES ('B', 3000, 5999);
INSERT INTO job_grades
VALUES('C', 6000, 9999);
INSERT INTO job_grades
VALUES('D', 10000, 14999);
INSERT INTO job_grades
VALUES('E', 15000, 24999);
INSERT INTO job_grades
VALUES('F', 25000, 40000);
*/# 1.查询员工的工资和工资级别SELECT salary,grade_level FROM employees e,job_grades j WHERE salary BETWEEN j.`lowest_sal` AND j.`highest_sal`;# (3)自连接# 1.查询员工名和其上级的名称.SELECT e.employee_id "员工id",e.last_name "员工姓名",m.employee_id "经理id",m.last_name "经理姓名" FROM employees e,employees m WHERE e.`manager_id`=m.`employee_id`;Nach dem Login kopieren Nach dem Login kopieren 学完了sql92标准的连接查询，尝试完成下面的练习题
答案：
1、
SELECT last_name,d.department_id,department_name
FROM employees e,departments d
WHERE e.department_id=d.department_id;
2、
SELECT e.job_id,d.location_id FROM employees e,departments d
WHERE d.department_id=e.department_id
AND e.department_id=90;
3、
SELECT last_name , department_name , l.location_id , city
FROM employees e,departments d,locations l
WHERE e.department_id=d.department_id AND d.location_id=l.location_id AND e.commission_pct IS NOT NULL;
4、
SELECT last_name , job_id , d.department_id , department_name
FROM employees e,departments d,locations l
WHERE e.department_id=d.department_id AND d.location_id=l.location_id AND l.city=‘Toronto’;
5、
SELECT department_name,job_title,MIN(salary)
FROM departments d,employees e,jobs j
WHERE d.department_id=e.department_id AND e.job_id = j.job_id
GROUP BY job_title,department_name;
6、
SELECT COUNT(),country_id FROM departments d,locations l
WHERE d.location_id=l.location_id
GROUP BY country_id
HAVING COUNT()>2;
7、
SELECT e1.last_name “employees”,e1.employee_id “Emp#”,e2.last_name “manager”,e2.employee_id “Mgr#”
FROM employees e1,employees e2
WHERE e1.manager_id=e2.employee_id AND e1.last_name=‘kochhar’;
【sql99标准】# (1)等值连接# 1.查询员工名,部门名SELECT last_name,department_name
FROM employees eINNER JOIN departments dON e.department_id=d.department_id;# 2.查询名字中包含e的员工名和工种名(添加筛选)SELECT last_name,job_titleFROM employees eINNER JOIN jobs jON e.job_id=j.job_idWHERE last_name LIKE '%e%' OR job_title LIKE '%e%';# 3.查询部门个数>3的城市名和部门个数(分组+筛选)SELECT city,COUNT(*) "部门个数"FROM departments dINNER JOIN locations lON d.location_id=l.location_idGROUP BY cityHAVING COUNT(*)>3;# 4.查询哪个部门的部门员工个数>3的部门名和员工个数,并按个数降序(排序)SELECT department_name "部门名",COUNT(*) "员工个数"FROM departments dINNER JOIN employees eON d.department_id=e.department_idGROUP BY department_nameHAVING COUNT(*)>3ORDER BY COUNT(*) DESC;# 5.查询员工名、部门名、工种名、并按部门名排序SELECT last_name "员工名",department_name "部门名",job_title "工种名"FROM employees eINNER JOIN departments d ON d.department_id=e.department_idINNER JOIN jobs j ON e.job_id=j.job_idORDER BY department_name ;# (2)非等值连接# 查询员工工资级别SELECT salary,grade_levelFROM employees eJOIN job_grades j ON e.`salary` BETWEEN j.lowest_sal AND j.highest_sal;# 查询每个工资级别的个数>20的个数,并且按照工资级别降序排列SELECT COUNT(*),grade_levelFROM employees eJOIN job_grades j ON e.`salary` BETWEEN j.lowest_sal AND j.highest_salGROUP BY grade_levelHAVING COUNT(*)>20ORDER BY grade_level DESC;# (3)自连接# 查询员工的名字、上级的名字SELECT e1.last_name "员工名",e2.last_name "上级名"FROM employees e1JOIN employees e2 ON e1.manager_id=e2.employee_id;--------------------------------------------------------------------------------------------------------------# 二、外连接# 1.查询男朋友不在男神表的女神名# 左外连接SELECT NAME
FROM beauty LEFT OUTER JOIN boys ON beauty.boyfriend_id=boys.idWHERE boys.id IS NULL;# 右外连接SELECT NAMEFROM boys RIGHT OUTER JOIN beauty ON beauty.boyfriend_id=boys.idWHERE boys.id IS NULL;# 2.查询没有员工的部门SELECT d.department_name,e.employee_idFROM departments d LEFT JOIN employees e ON d.department_id=e.department_idWHERE e.manager_id IS NULL;SELECT * FROM employees WHERE employee_id=100;# 3.全外连接(不支持)# 全外连接就是就并集USE girls;SELECT b.*,bo.*FROM beauty bFULL JOIN boys boON b.boyfriend_id=bo.id;# 三.交叉连接# 使用99标准实现的笛卡尔乘积,使用cross代替了92中的,SELECT b.*,bo.*FROM beauty bCROSS JOIN boys bo Nach dem Login kopieren Nach dem Login kopieren 
学完了sql99标准的连接查询，尝试完成下面的练习题
答案：
一、
SELECT b.name,bo.*
FROM beauty b LEFT JOIN boys bo
ON b.boyfriend_id=bo.id
WHERE b.id>3;
二、
SELECT city “城市”,department_name “城市名”
FROM departments d RIGHT JOIN locations l
ON d.location_id=l.location_id
WHERE d.department_id IS NULL;
三、
SELECT d.department_name,e.*
FROM departments d LEFT JOIN employees e
ON d.department_id=e.department_id
WHERE d.department_name IN (‘SAL’,‘IT’);
七、子查询
含义：出现在其他语句中的select语句，称为子查询或内查询；外部的查询语句，称为主查询或外查询。
按子查询出现的位置分类：
- select后面 (仅支持标量子查询)
- from后面 (支持表子查询)
- where或having后面 (支持标量、行、列子查询)☆☆☆
- exists后面 (又叫相关子查询，支持表子查询)
按结果集的行列数分类：
- 标量子查询(结果集只有一行一列)
- 列子查询(结果集只有一列多行)
- 行子查询(结果集有一行多列)
- 表子查询(结果集一般为多行多列)
【where和having后的子查询】(支持标量、行、列子查询)# 1.单个标量子查询# 查询工资比Abel工资高的员工名SELECT last_name,salary
FROM employees
WHERE salary>(SELECT salary FROM employees WHERE last_name='Abel');# 2。多个标量子查询# 返回job_id与141号相同,salary比143号员工多的员工的姓名、job_id、工资。SELECT last_name,job_id,salary
FROM employeesWHERE job_id=(
SELECT job_id FROM employees WHERE employee_id=141)
AND salary>(SELECT salary FROM employees WHERE employee_id=143);# 3。标量子查询+分组函数# 返回工资最少的员工的last_name、job_id和salarySELECT last_name,job_id,salary
FROM employees
WHERE salary=(SELECT MIN(salary) FROM employees);# 4。标量子查询+having子句# 查询最低工资 >50号部门最低工资的 部门id和其最低工资SELECT department_id,MIN(salary) FROM employees GROUP BY department_idHAVING MIN(salary)>(SELECT MIN(salary) FROM employees WHERE department_id=50);
# 5.列子查询(多行子查询)# 返回location_id是1400或1700的部门中的所有员工姓名.SELECT last_name FROM employees
WHERE department_id IN (
SELECT DISTINCT department_id FROM departments WHERE location_id IN(1400,1700));# 返回其它工种中比job_id为'IT_PROG'工种中任一工资低的员工的工号、姓名、job_id、以及salarySELECT employee_id,last_name,job_id,salary FROM employeesWHERE salary<any>'IT_PROG';# 返回其它工种中比job_id为'IT_PROG'工种中所有工资低的员工的工号、姓名、job_id、以及salarySELECT employee_id,last_name,job_id,salary FROM employeesWHERE salary<all>'IT_PROG';# 6.行子查询(一行多列或多列多行子查询)# 查询出员工编号最小并且工资最高的员工信息# 方式一SELECT * FROM employees WHERE (employee_id,salary)=(SELECT MIN(employee_id),MAX(salary) FROM employees);# 方式二SELECT * FROM employees
WHERE employee_id=(SELECT MIN(employee_id) FROM employees)AND salary=(SELECT MAX(salary) FROM employees)</all></any> Nach dem Login kopieren 【select后的子查询】：(仅支持标量子查询)# 1.查询每个部门的员工个数SELECT d.*,(SELECT COUNT(*) FROM employees e WHERE e.department_id=d.department_id) "员工个数"FROM departments d;# 2.查询员工号=102的部门名SELECT (
SELECT department_name FROM departments d INNER JOIN employees e ON d.department_id=e.department_id WHERE e.employee_id=102) 部门名; Nach dem Login kopieren 【from后面的子查询】(支持表子查询)# 1.查询每个部门的平均工资的工资等级,即将子查询后的结果充当一张表,要求必须起别名SELECT a.*,g.grade_level "工资等级"FROM (
SELECT AVG(salary) ag,department_id FROM employees GROUP BY department_id) aINNER JOIN job_grades gON a.ag BETWEEN lowest_sal AND highest_sal; Nach dem Login kopieren 【existts后面的子查询】(又叫相关子查询,可以用in代替)# exists结果只会是1或0 ：SELECT EXISTS(SELECT * FROM employees);# 1.查询有员工名的部门名SELECT department_nameFROM departments dWHERE EXISTS(SELECT * FROM employees e WHERE d.department_id=e.department_id); Nach dem Login kopieren 学完了子查询，尝试完成下面的习题
答案：
1、思路:①查询Zlotkey的部门②查询部门号=①的员工姓名和工资
SELECT last_name,salary
FROM employees
WHERE department_id=(
SELECT department_id
FROM employees
WHERE last_name=‘Zlotkey’2、思路:①查询平均工资②查询工资比①高的员工的工号、姓名、工资
SELECT employee_id,last_name,salary
FROM employees
WHERE salary>(SELECT AVG(salary) FROM employees);
3、思路:①查询各部门平均工资②查询各部门工资比①高的员工的员工号、姓名、工资
SELECT employee_id,last_name,salary,e.department_id
FROM (
SELECT AVG(salary) ag,department_id
FROM employees e
GROUP BY department_id ON a.department_id=e.department_id
WHERE e.salary>a.ag
4、思路:①查询姓名中包含字母u的员工的部门②查询部门号=①中任意一个的员工的工号和姓名
SELECT employee_id “员工号”,last_name “姓名”
FROM employees
WHERE department_id IN(
SELECT DISTINCT department_id
FROM employees
WHERE last_name LIKE ‘%u%’5、思路:①查询location_id=1700的部门②查询在①部门中工作的员工的员工号
SELECT employee_id
FROM employees
WHERE department_id IN(
SELECT DISTINCT department_id
FROM departments
WHERE location_id=17006、思路:①查询姓名为K_ing的员工编号②查询manager_id=①的姓名和工资
SELECT last_name “员工姓名”,salary “工资”
FROM employees
WHERE manager_id IN(
SELECT employee_id
FROM employees
WHERE last_name=‘K_ing’7、思路:①查询最高工资②查询工资=①的姓.名
SELECT CONCAT(first_name,last_name) “姓.名”
FROM employees
WHERE salary=(SELECT MAX(salary) FROM employees);
如果觉得做得不过瘾，可以继续挑战下面的子查询经典案例:
答案：
1、思路:①查询最低工资②查询工资=①的last_name, salary
SELECT last_name, salary
FROM employees
WHERE salary=(SELECT MIN(salary) FROM employees)
2、思路一:①查询各部门的平均工资;②查询①结果上的最低平均工资③查询哪个部门的平均工资=②;④查询部门信息
SELECT d.*
FROM departments d
WHERE d.department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)=(
SELECT MIN(ag)
FROM (
SELECT AVG(salary) ag,department_id
FROM employees
GROUP BY department_id思路二:①使用排序求出最低平均工资的部门编号②查询部门信息
SELECT * FROM departments
WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
ORDER BY AVG(salary) ASC
LIMIT 13、思路:①查询各部门平均工资;②查询最低平均工资的部门编号
SELECT d.* ,ag
FROM departments d
JOIN (
SELECT AVG(salary) ag,department_id
FROM employees
GROUP BY department_id
ORDER BY AVG(salary) ASC
LIMIT 1 ON d.department_id=a.department_id;
4、思路:①查询job的平均工资最高的job_id;②查询job信息
SELECT *
FROM jobs
WHERE job_id=(
SELECT job_id
FROM employees
GROUP BY job_id
ORDER BY AVG(salary) DESC
LIMIT 15、思路:①查询公司平均工资;②查询每个部门的平均工资;最后筛选②中平均工资 > ①
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)>(
SELECT AVG(salary)
FROM employees6、思路:①查询有manager的员工编号;②查询编号在①中的详细信息
SELECT * FROM employees
WHERE employee_id IN (SELECT DISTINCT manager_id FROM employees);
7、思路:①查询各部门最高工资中最低的那个部门id;②查询①部门的最低工资啊
SELECT MIN(salary) FROM employees WHERE department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
ORDER BY MAX(salary) ASC
LIMIT 18、思路:①查询平均工资最高的部门编号;②将employees和departments连接查询,筛选条件是①
SELECT last_name, d.department_id, email,salary
FROM employees e
INNER JOIN departments d ON d.manager_id=e.employee_id
WHERE d.department_id=(
SELECT department_id
FROM employees
GROUP BY department_id
ORDER BY AVG(salary) DESC
LIMIT 1
八、分页查询
应用场景:当要显示的数据一页显示不全,需要分页提交sql请求。
语法:
select 查询列表
from 表
[join type join 表2
on 连接条件
where 筛选条件
group by 分组字段
having 分组后的筛选
order by]
limit offset,size;
offset:从0开始的起始索引,若省略默认从第一条开始
size:要显示的条目个数
执行顺序:from > join > on > where > group by > having > select > order by > limit (limit语法和执行都在最后)
limit分页公式：
select * from 表 limit (page-1)*size,size;(要显示的页数为page,每页的条目数为size)
# 1.查询前五条员工信息SELECT * FROM employees LIMIT 5;# 2.查询第11条到第25条SELECT * FROM employees LIMIT 10,15# 3.有奖金的员工信息,并且显示出工资较高的前10名SELECT * FROM employeesWHERE commission_pct IS NOT NULLORDER BY salaryLIMIT 10; Nach dem Login kopieren 九、联合查询
定义：将多条查询语句的结果合并成一个结果。
语法：查询语句1 union 查询语句2 unin ... 查询语句n
应用场景：当要查询的结果来自多个没有连接关系的表,但查询的信息一致时，最适合使用union。
注意事项：
- 要求多条查询语句的查询列数是一致的
- 要求多条查询语句查询的每一列的类型和顺序最好一致.
- union默认去重,如果使用union all可以关闭去重
- 大多数情况下，union的查询效率比or高。
# 1.查询部门编号>90或邮箱包含a的员工信息SELECT * FROM employees WHERE department_id>90 OR email LIKE '%a%';SELECT * FROM employees WHERE department_id>90 UNION SELECT * FROM employees WHERE email LIKE '%a%'; Nach dem Login kopieren 更多相关免费学习推荐：mysql教程(视频)
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