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(PHP 5 >= 5.3.0, PHP 7)
date_diff — 别名 DateTime::diff()
此函数是该函数的别名: DateTime::diff()
[#1] vladimir-nt at mail dot ru [2015-10-13 00:11:29]
My simple function to count up the number of weekdays between the dates (inclusive for both ends), one can add a holidays between the dates to take them into account as well as the weekends, the weekend days could also be changed.
function count_week_days($__date_from, $__date_to, $__holidays_between=array(), $__weekend_days=array(5,6)) {
$total_days_count = $__date_to > $__date_from ? round(($__date_to - $__date_from)/(24*3600)) : 0;
$full_weeks_count = floor($total_days_count/7);
$weekend_days_count = $full_weeks_count*count($__weekend_days);
$days_left_uncovered = $total_days_count - $full_weeks_count*7;
for($i = 0; $i < $days_left_uncovered; $i++) {
$date_to_check = $i ? strtotime("+{$i} day", $__date_from) : $__date_from;
if(in_array(date('N', $date_to_check), $__weekend_days)) {
$weekend_days_count++;
}
}
$week_days_count = $total_days_count - $weekend_days_count - count($__holidays_between);
return $week_days_count;
}
Tests:
print "\n 12.10.2015 to 10.10.2015 diff=".count_week_days(strtotime('12.10.2015'), strtotime('10.10.2015'));
print "\n 12.10.2015 to 13.10.2015 diff=".count_week_days(strtotime('12.10.2015'), strtotime('13.10.2015'));
print "\n 12.10.2015 to 15.10.2015 diff=".count_week_days(strtotime('12.10.2015'), strtotime('26.10.2015'));
print "\n 12.10.2015 to 13.10.2015 diff=".count_week_days(strtotime('12.10.2015'), strtotime('13.10.2016'));
print "\n 12.10.2015 to 13.10.2015 diff=".count_week_days(strtotime('12.10.2015'), strtotime('12.11.2015'));
print "\n 12.10.2015 to 13.10.2015 diff=".count_week_days(strtotime('12.10.2015'), strtotime('12.11.2015'), array(strtotime('07.11.2015')));
Results:
12.10.2015 to 10.10.2015 diff=0
12.10.2015 to 13.10.2015 diff=1
12.10.2015 to 15.10.2015 diff=10
12.10.2015 to 13.10.2015 diff=263
12.10.2015 to 13.10.2015 diff=23
12.10.2015 to 13.10.2015 diff=22
[#2] tuxedobob [2015-07-23 16:32:47]
Even the top rated comment here, Sergio Abreu's, doesn't treat leap years entirely correctly. It should work between 1901 and 2099, but outside that it'll be a little off.
If you want to find out the number of days between two dates, use below. You can change to a different unit from that. It looks a little insane, but keep in mind the full set of rules for leap years:
If the year is divisible by 4, it's a leap year...
- unless the year is divisible by 100, then it isn't...
- - unless the year is divisible by 400, then it really is.
So in the functions below, we find the total numbers of days in full years since the mythical 1/1/0001, then add the number of days before the current one in the year passed. Do this for each date, then return the absolute value of the difference.
function days_diff($d1, $d2) {
$x1 = days($d1);
$x2 = days($d2);
if ($x1 && $x2) {
return abs($x1 - $x2);
}
}
function days($x) {
if (get_class($x) != 'DateTime') {
return false;
}
$y = $x->format('Y') - 1;
$days = $y * 365;
$z = (int)($y / 4);
$days += $z;
$z = (int)($y / 100);
$days -= $z;
$z = (int)($y / 400);
$days += $z;
$days += $x->format('z');
return $days;
}
[#3] Azuro [2015-04-01 10:12:09]
I had to find the difference between two days (here is my solution without Date_diff()) :
$current_date = date("U")
$selected_date_stamp = mktime(0,0,0,$your_month,$your_day,$your_year);
$selected_date = date("U",$selected_date_stamp);
$difference = round (($current_date - $selected_date)/(3600*24));
echo "The difference is :" . $difference . "<br/>";
[#4] maniarpratik at gmail dot com [2015-01-30 12:09:24]
This function will return count of sunday between inputed dates.
<?php
function CountSunday($from,$to)
{
$from=date('d-m-Y',strtotime($from));
$to=date('d-m-Y',strtotime($to));
$cnt=0;
$nodays=(strtotime($to) - strtotime($from))/ (60 * 60 * 24); //it will count no. of days
$nodays=$nodays+1;
for($i=0;$i<$nodays;$i++)
{
$p=0;
list($d, $m, $y) = explode("-",$from);
$datetime = strtotime("$d-$m-$y");
$nextday = date('d-m-Y',strtotime("+1 day", $datetime)); //this will add one day in from date (from date + 1)
if($i==0)
$p=date('w',strtotime($from));
else
$p=date('w',strtotime($nextday));
if($p==0) // check whethere value is 0 then its sunday
$cnt++; //count variable of sunday
$from=$nextday;
$p++;
}
return $cnt;
}
?>
[#5] qrworld.net [2014-12-02 14:32:20]
Here you have in this post http://softontherocks.blogspot.com/2014/12/calcular-la-edad-con-php.html the code to get the age of a person specifying the date of birth:
function getAge($birthdate){
$adjust = (date("md") >= date("md", strtotime($birthdate))) ? 0 : -1; // Si a??n no hemos llegado al d??a y mes en este a?o restamos 1
$years = date("Y") - date("Y", strtotime($birthdate)); // Calculamos el n??mero de a?os
return $years + $adjust; // Sumamos la diferencia de a?os m??s el ajuste
}
[#6] jesushuertaarrabal at gmail dot com [2014-10-03 00:48:42]
A way to verify a correct date getting your age
if (isset($_POST['birthday'])){
if (preg_match("/^[0-9]{4}-[0-1][0-9]-[0-3][0-9]$/",$_POST['birthday'])){
$items = explode("-", $_POST['birthday']);
if (checkdate($items[1], $items[2], $items[0])){ //checkdate(m-d-y)
//If you were born in a lip-year or lip - 1, then we have to add 5 days, else, we add 4 days
if ((0 == $items[0] % 4) && (0 != $items[0] % 100) || (0 == $items[0] % 400))
$bis = 4;
else
$bis = 5;
if (date_diff(date_create($_POST['birthday']) , date_create(date('Y-m-d')))->format("%R%a days") > (6569 + $bis)) //365*18
$print .= 'Birthday date: ' . $_POST['birthday'] . '<br>';
else
$error[] = -1;
}else
$error[] = -2;
}else
$error[] = -3;
}else
$error[] = -4;
}
[#7] SunilKmCharde [2014-05-21 08:07:37]
Powerful Function to get two date difference.
//////////////////////////////////////////////////////////////////////
//PARA: Date Should In YYYY-MM-DD Format
//RESULT FORMAT:
// '%y Year %m Month %d Day %h Hours %i Minute %s Seconds' => 1 Year 3 Month 14 Day 11 Hours 49 Minute 36 Seconds
// '%y Year %m Month %d Day' => 1 Year 3 Month 14 Days
// '%m Month %d Day' => 3 Month 14 Day
// '%d Day %h Hours' => 14 Day 11 Hours
// '%d Day' => 14 Days
// '%h Hours %i Minute %s Seconds' => 11 Hours 49 Minute 36 Seconds
// '%i Minute %s Seconds' => 49 Minute 36 Seconds
// '%h Hours => 11 Hours
// '%a Days => 468 Days
//////////////////////////////////////////////////////////////////////
function dateDifference($date_1 , $date_2 , $differenceFormat = '%a' )
{
$datetime1 = date_create($date_1);
$datetime2 = date_create($date_2);
$interval = date_diff($datetime1, $datetime2);
return $interval->format($differenceFormat);
}
[#8] Chiheb Nabil [2013-02-09 02:01:40]
here a little solution of problem of missing date_diff function with php versions below 5.3.0
<?php
function IntervalDays($CheckIn,$CheckOut){
$CheckInX = explode("-", $CheckIn);
$CheckOutX = explode("-", $CheckOut);
$date1 = mktime(0, 0, 0, $CheckInX[1],$CheckInX[2],$CheckInX[0]);
$date2 = mktime(0, 0, 0, $CheckOutX[1],$CheckOutX[2],$CheckOutX[0]);
$interval =($date2 - $date1)/(3600*24);
// returns numberofdays
return $interval ;
}
?>
[#9] programacion at mundosica dot com [2012-04-17 22:36:08]
Other data_diff aviable for php5.3>=
<?php
// Author: el pinche <fitorec>
function otherDiffDate($end='2020-06-09 10:30:00', $out_in_array=false){
$intervalo = date_diff(date_create(), date_create($end));
$out = $intervalo->format("Years:%Y,Months:%M,Days:%d,Hours:%H,Minutes:%i,Seconds:%s");
if(!$out_in_array)
return $out;
$a_out = array();
array_walk(explode(',',$out),
function($val,$key) use(&$a_out){
$v=explode(':',$val);
$a_out[$v[0]] = $v[1];
});
return $a_out;
}
?>
#example 1
<?php
echo otherDiffDate();
?>
out1
Years:08,Months:01,Days:22,Hours:17,Minutes:5,Seconds:26
example2
<?php
print_r(otherDiffDate('2020-01-01 20:30:00',true));
?>
out2
Array
(
[Years] => 07
[Months] => 08
[Days] => 15
[Hours] => 03
[Minutes] => 3
[Seconds] => 48
)
[#10] Toine (contact at toine dot pro) [2011-08-26 07:22:16]
This is a very simple function to calculate the difference between two timestamp values.
<?php
function diff($start,$end = false) {
// Checks $start and $end format (timestamp only for more simplicity and portability)
if(!$end) { $end = time(); }
if(!is_numeric($start) || !is_numeric($end)) { return false; }
// Convert $start and $end into EN format (ISO 8601)
$start = date('Y-m-d H:i:s',$start);
$end = date('Y-m-d H:i:s',$end);
$d_start = new DateTime($start);
$d_end = new DateTime($end);
$diff = $d_start->diff($d_end);
// return all data
$this->year = $diff->format('%y');
$this->month = $diff->format('%m');
$this->day = $diff->format('%d');
$this->hour = $diff->format('%h');
$this->min = $diff->format('%i');
$this->sec = $diff->format('%s');
return true;
}
$start = strtotime('1985/02/09 13:54:17');
$end = strtotime('2012/12/12 17:30:21');
$myClass = new myClass();
$myClass->Diff($start,$end);
// Display result
echo 'Year: '.$myClass->Year;
echo '<br />Month: '.$myClass->Month;
echo '<br />Day: '.$myClass->Day;
echo '<br />Hour: '.$myClass->Hour;
echo '<br />Min: '.$myClass->Min;
echo '<br />Sec: '.$myClass->Sec;
// Display only month for all duration
$month = ($myClass->Year * 12) + $myClass->Month;
echo '<br />Total month: '.$month;
// if you want you can use this function without $end value :
$myClass->Diff($start);
// Automatically the end is the current timestamp
?>
[#11] vglebov at gmail dot com [2011-05-25 23:59:31]
Get the difference between the dates without days off
<?php
function get_date_diff($date1, $date2) {
$holidays = 0;
for ($day = $date2; $day < $date1; $day += 24 * 3600) {
$day_of_week = date('N', $day);
if($day_of_week > 5) {
$holidays++;
}
}
return $date1 - $date2 - $holidays * 24 * 3600;
}
function test_get_date_diff()
{
$datas = array(
array('Fri 20 May 2011 14:00:00', 'Fri 20 May 2011 13:00:00', 1 * 3600),
array('Sat 21 May 2011 15:00:00', 'Fri 20 May 2011 13:00:00', 2 * 3600),
array('Sun 22 May 2011 16:00:00', 'Fri 20 May 2011 13:00:00', 3 * 3600),
array('Mon 23 May 2011 14:00:00', 'Fri 20 May 2011 13:00:00', 25 * 3600),
array('Fri 27 May 2011 13:00:00', 'Fri 13 May 2011 13:00:00', 24 * 10 * 3600),
);
foreach ($datas as &$data) {
$actual = get_date_diff(strtotime($data[0]), strtotime($data[1]));
if ($actual != $data[2]) {
echo "Test for get_date_diff faled expected {$data[2]} but was {$actual}, date1: {$data[0]}, date2: {$data[1]}.<br>";
}
}
}
test_get_date_diff($data);
?>
[#12] kshegunov at gmail dot com [2011-01-10 09:26:57]
Here is how I solved the problem of missing date_diff function with php versions below 5.3.0
The function accepts two dates in string format (recognized by strtotime() hopefully), and returns the date difference in an array with the years as first element, respectively months as second, and days as last element.
It should be working in all cases, and seems to behave properly when moving through February.
<?php
function dateDifference($startDate, $endDate)
{
$startDate = strtotime($startDate);
$endDate = strtotime($endDate);
if ($startDate === false || $startDate < 0 || $endDate === false || $endDate < 0 || $startDate > $endDate)
return false;
$years = date('Y', $endDate) - date('Y', $startDate);
$endMonth = date('m', $endDate);
$startMonth = date('m', $startDate);
// Calculate months
$months = $endMonth - $startMonth;
if ($months <= 0) {
$months += 12;
$years--;
}
if ($years < 0)
return false;
// Calculate the days
$offsets = array();
if ($years > 0)
$offsets[] = $years . (($years == 1) ? ' year' : ' years');
if ($months > 0)
$offsets[] = $months . (($months == 1) ? ' month' : ' months');
$offsets = count($offsets) > 0 ? '+' . implode(' ', $offsets) : 'now';
$days = $endDate - strtotime($offsets, $startDate);
$days = date('z', $days);
return array($years, $months, $days);
}
?>
[#13] Sergio Abreu [2010-06-26 07:22:49]
<?php
function s_datediff( $str_interval, $dt_menor, $dt_maior, $relative=false){
if( is_string( $dt_menor)) $dt_menor = date_create( $dt_menor);
if( is_string( $dt_maior)) $dt_maior = date_create( $dt_maior);
$diff = date_diff( $dt_menor, $dt_maior, ! $relative);
switch( $str_interval){
case "y":
$total = $diff->y + $diff->m / 12 + $diff->d / 365.25; break;
case "m":
$total= $diff->y * 12 + $diff->m + $diff->d/30 + $diff->h / 24;
break;
case "d":
$total = $diff->y * 365.25 + $diff->m * 30 + $diff->d + $diff->h/24 + $diff->i / 60;
break;
case "h":
$total = ($diff->y * 365.25 + $diff->m * 30 + $diff->d) * 24 + $diff->h + $diff->i/60;
break;
case "i":
$total = (($diff->y * 365.25 + $diff->m * 30 + $diff->d) * 24 + $diff->h) * 60 + $diff->i + $diff->s/60;
break;
case "s":
$total = ((($diff->y * 365.25 + $diff->m * 30 + $diff->d) * 24 + $diff->h) * 60 + $diff->i)*60 + $diff->s;
break;
}
if( $diff->invert)
return -1 * $total;
else return $total;
}
?>
[#14] Flavio Tubino [2010-05-26 17:37:51]
This is a very simple function to calculate the difference between two datetime values, returning the result in seconds. To convert to minutes, just divide the result by 60. In hours, by 3600 and so on.
Enjoy.
<?php
function time_diff($dt1,$dt2){
$y1 = substr($dt1,0,4);
$m1 = substr($dt1,5,2);
$d1 = substr($dt1,8,2);
$h1 = substr($dt1,11,2);
$i1 = substr($dt1,14,2);
$s1 = substr($dt1,17,2);
$y2 = substr($dt2,0,4);
$m2 = substr($dt2,5,2);
$d2 = substr($dt2,8,2);
$h2 = substr($dt2,11,2);
$i2 = substr($dt2,14,2);
$s2 = substr($dt2,17,2);
$r1=date('U',mktime($h1,$i1,$s1,$m1,$d1,$y1));
$r2=date('U',mktime($h2,$i2,$s2,$m2,$d2,$y2));
return ($r1-$r2);
}
?>
[#15] tom at knapp2meter dot tk [2009-04-16 08:06:11]
A simple way to get the time lag (format: <hours>.<one-hundredth of one hour>).
Hier ein einfacher Weg zur Bestimmung der Zeitdifferenz (Format: <Stunden>.<hundertstel Stunde>).
<?php
function GetDeltaTime($dtTime1, $dtTime2)
{
$nUXDate1 = strtotime($dtTime1->format("Y-m-d H:i:s"));
$nUXDate2 = strtotime($dtTime2->format("Y-m-d H:i:s"));
$nUXDelta = $nUXDate1 - $nUXDate2;
$strDeltaTime = "" . $nUXDelta/60/60; // sec -> hour
$nPos = strpos($strDeltaTime, ".");
if (nPos !== false)
$strDeltaTime = substr($strDeltaTime, 0, $nPos + 3);
return $strDeltaTime;
}
?>