<?php
//数据库操作类
class Model{
private $host; //数据库地址
private $user; //数据库用户名
private $pwd; //数据库密码
private $tabName; //表名
private $preFix; //表前缀
private $dbName; //数据库名
private $charset; //字符
private $link=null; //数据连接对象
function __construct($tabName = ''){
$this->host = DB_HOST;
$this->user = DB_USER;
$this->pwd = DB_PWD;
$this->charset = CHARSET;
$this->preFix = DB_PREFIX;
$this->dbName = DB_NAME;
if($tabName == ''){
$this->tabName = $this->prefix.strtolower(substr(get_class($this),0,-5)) ;
}else{
$this->tabName = $this->preFix.$tabName;
}
$this->link = $this->connect();
}
private function connect(){
$link = @mysqli_connect($this->host,$this->user,$this->pwd,$this->dbname) or die('数据库连接错误');
if(!$link){
return false;
}
mysqli_set_charset($link,$this->charset);
return $link;
}
public function insert(array $data){
//var_dump($data);
//INSERT INTO user(name,sex,age) VALUE();
$key = $val = '';
foreach($data as $k=>$v){
$key .='`'.$k.'`,';
$val .="'".$v."',";
}
$key = rtrim($key,',');
$val = rtrim($val,',');
// var_dump($key);
// var_dump($val);
$sql = "INSERT INTO {$this->tabName} ({$key}) VALUES ({$val})";
echo $sql;
return $this->exec($sql);
}
private function exec($sql){
$result = mysqli_query($this->link,$sql);
if($result && mysqli_affected_rows($this->link) > 0){
return mysqli_insert_id($this->link) ?? mysqli_affected_rows($this->link);
}else{
return false;
}
}
}
//调用方法，为什么不成功？总是插入不进去，提示false;??
<?php
$m = new Model('user');
// echo '<pre>';
// var_dump($m);
$_POST = array('name'=>'小驴','age'=>'20','sex'=>'1');
$result = $m->insert($_POST);
var_dump($result);
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终于知道原因了！！已搞定！
按照代码应该是连接的问题，你可以尝试打印$link
看代码也没有问题，sql语句在数据库中也是可以正常执行的，但是调用类的插入方法之后，就不行了，这是怎么回事？