Fehler bei der Sortierung des MySQL-Datums

Question

SELECT
co.id,
IFNULL( oe.follow_status, 'unFollow' ) AS followStatus,
co.due_time 
FROM
car_order co
LEFT JOIN order_expire oe ON oe.order_id = co.id 
WHERE
co.type = '贷款' 
AND co.STATUS = '已放款' 
AND co.approve_status != '结清成功' 
AND date_FORMAT( co.due_time, '%Y-%m-%d' ) <= '2022-10-29' 
ORDER BY
field( oe.follow_status, 'unFollow', 'follow' ),
co.due_time DESC,
co.id DESC

Falsche Datumssortierung. Wie soll ich es schreiben?

Answer 1

SELECT
co.id,
IFNULL( oe.follow_status, 'unFollow' ) AS followStatus,
co.due_time 
FROM
car_order co
LEFT JOIN order_expire oe ON oe.order_id = co.id 
WHERE
co.type = '贷款' 
AND co.STATUS = '已放款' 
AND co.approve_status != '结清成功' 
AND co.due_time 
您应该改为通过 IFNULL 别名 followStatus 进行排序。

Answer 2

假设 due_time 是时间戳列，您应该能够直接将其与日期文字进行比较：

SELECT co.id,
       IFNULL(oe.follow_status, 'unFollow') AS followStatus,
       co.due_time 
FROM car_order co
LEFT JOIN order_expire oe ON oe.order_id = co.id 
WHERE co.type = '贷款' AND 
      co.STATUS = '已放款' AND
      co.approve_status != '结清成功' AND
      co.due_time 
DATE_FORMAT() 函数用于将日期/时间戳转换为字符串，但这里不需要它，因为可以直接比较日期/时间戳列。