javascript - 关于网易云音乐爬虫的api接口？

Question

抓包能力有限，分析了一下网易云音乐的一些api接口，但是关于它很多post请求都是加了密，没有弄太明白。之前在知乎看到过一个豆瓣工程师写的教程，但是被投诉删掉了，请问有网友fork了的吗？因为我觉得他写的代码都比较pythonic，符合pep8规范。知乎另外几名大V比如@路人甲虽然经常分享数据，但是很少分享源代码，github也没有公布，公开过的代码我觉得他很多基础的pep8细节都忽略了，而且他的爬虫的效率非常低，比如爬网易10k+评论，在专栏说爬了6个小时之类的很辛苦之类的话，但是看他的代码别提异步了，甚至连多线程/多进程都没有使用，觉得有点水。前面那位大神还是真的有很多干货。

不一定要是python，任意语言都行，各位网友能否分享一些分析网易云音乐api接口的设计博客教程/大型项目？

Answer 1

网易云音乐常用API浅析
新版WebAPI分析
使用selenium简单点

//里面的php demo
function curl_get($url)
{
    $refer = "http://music.163.com/";
    $header[] = "Cookie: " . "appver=1.5.0.75771;";
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_HTTPHEADER, $header);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_BINARYTRANSFER, true);
    curl_setopt($ch, CURLOPT_REFERER, $refer);
    $output = curl_exec($ch);
    curl_close($ch);
    return $output;
}
 
function music_search($word, $type)
{
    $url = "http://music.163.com/api/search/pc";
    $post_data = array(
        's' => $word,
        'offset' => '0',
        'limit' => '20',
        'type' => $type,
    );
    $referrer = "http://music.163.com/";
    $URL_Info = parse_url($url);
    $values = [];
    $result = '';
    $request = '';
    foreach ($post_data as $key => $value) {
        $values[] = "$key=" . urlencode($value);
    }
    $data_string = implode("&", $values);
    if (!isset($URL_Info["port"])) {
        $URL_Info["port"] = 80;
    }
    $request .= "POST " . $URL_Info["path"] . " HTTP/1.1\n";
    $request .= "Host: " . $URL_Info["host"] . "\n";
    $request .= "Referer: $referrer\n";
    $request .= "Content-type: application/x-www-form-urlencoded\n";
    $request .= "Content-length: " . strlen($data_string) . "\n";
    $request .= "Connection: close\n";
    $request .= "Cookie: " . "appver=1.5.0.75771;\n";
    $request .= "\n";
    $request .= $data_string . "\n";
    $fp = fsockopen($URL_Info["host"], $URL_Info["port"]);
    fputs($fp, $request);
    $i = 1;
    while (!feof($fp)) {
        if ($i >= 15) {
            $result .= fgets($fp);
        } else {
            fgets($fp);
            $i++;
        }
    }
    fclose($fp);
    return $result;
}
 
function get_music_info($music_id)
{
    $url = "http://music.163.com/api/song/detail/?id=" . $music_id . "&ids=%5B" . $music_id . "%5D";
    return curl_get($url);
}
 
function get_artist_album($artist_id, $limit)
{
    $url = "http://music.163.com/api/artist/albums/" . $artist_id . "?limit=" . $limit;
    return curl_get($url);
}
 
function get_album_info($album_id)
{
    $url = "http://music.163.com/api/album/" . $album_id;
    return curl_get($url);
}
 
function get_playlist_info($playlist_id)
{
    $url = "http://music.163.com/api/playlist/detail?id=" . $playlist_id;
    return curl_get($url);
}
 
function get_music_lyric($music_id)
{
    $url = "http://music.163.com/api/song/lyric?os=pc&id=" . $music_id . "&lv=-1&kv=-1&tv=-1";
    return curl_get($url);
}
 
function get_mv_info()
{
    $url = "http://music.163.com/api/mv/detail?id=319104&type=mp4";
    return curl_get($url);
}

Answer 2

https://github.com/sqaiyan/ne...链接描述

这里，可以看官网的js源码，也可以抓客户端包看接口。现在客户端都采用最新的接口，加密算法不知道。但是官网的weapi接口上面有加密的算法。主要还是要猜字段。很多最老的api也可以用没有加密，但是一些接口被废弃，而且和新接口返回字段也不一样。我上面写的应该够你用的。不够就自己去抓包分析猜字段。基本所有接口都能找到

Answer 3

java 版本的网易 api 加密方式：
加密工具类
https://github.com/junbaor/netease/blob/master/src/main/java/com/junbaor/netease/common/EncryptUtils.java
调用测试类
https://github.com/junbaor/netease/blob/master/src/test/java/com/junbaor/netease/common/TestApi.java

希望对你有所帮助。

package com.junbaor.netease.common;

import org.apache.commons.lang3.RandomStringUtils;
import sun.misc.BASE64Encoder;

import javax.crypto.Cipher;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;
import java.math.BigInteger;
import java.util.HashMap;
import java.util.Map;

public class EncryptUtils {

    private final static String modulus = "00e0b509f6259df8642dbc35662901477df22677ec152b5ff68ace615bb7" +
            "b725152b3ab17a876aea8a5aa76d2e417629ec4ee341f56135fccf695280" +
            "104e0312ecbda92557c93870114af6c9d05c4f7f0c3685b7a46bee255932" +
            "575cce10b424d813cfe4875d3e82047b97ddef52741d546b8e289dc6935b" +
            "3ece0462db0a22b8e7";

    private final static String nonce = "0CoJUm6Qyw8W8jud";
    private final static String pubKey = "010001";

    private static final String PARAMS = "params";
    private static final String ENCSECKEY = "encSecKey";

    public static Map<String, String> encrypt(String text) {
        String secKey = RandomStringUtils.random(16, "0123456789abcde");
        String encText = aesEncrypt(aesEncrypt(text, nonce), secKey);
        String encSecKey = rsaEncrypt(secKey, pubKey, modulus);

        Map<String, String> map = new HashMap<String, String>();
        map.put(PARAMS, encText);
        map.put(ENCSECKEY, encSecKey);
        return map;
    }

    private static String aesEncrypt(String text, String key) {
        try {
            IvParameterSpec iv = new IvParameterSpec("0102030405060708".getBytes("UTF-8"));
            SecretKeySpec skeySpec = new SecretKeySpec(key.getBytes("UTF-8"), "AES");

            Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
            cipher.init(Cipher.ENCRYPT_MODE, skeySpec, iv);

            byte[] encrypted = cipher.doFinal(text.getBytes());

            return new BASE64Encoder().encode(encrypted);
        } catch (Exception e) {
            return "";
        }
    }

    private static String rsaEncrypt(String text, String pubKey, String modulus) {
        text = new StringBuilder(text).reverse().toString();
        BigInteger rs = new BigInteger(String.format("%x", new BigInteger(1, text.getBytes())), 16)
                .modPow(new BigInteger(pubKey, 16), new BigInteger(modulus, 16));
        String r = rs.toString(16);
        if (r.length() >= 256) {
            return r.substring(r.length() - 256, r.length());
        } else {
            while (r.length() < 256) {
                r = 0 + r;
            }
            return r;
        }
    }

}

Answer 4

musicbox-基于Python
看完你就会。

Answer 5

https://github.com/wenhaolian...