如何终止用python写的socket服务端程序?
黄舟
黄舟 2017-04-18 10:20:24
0
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用python写了一个socket服务端的程序,但是启动之后由于监听连接的是一个死循环,所以不知道怎样在cmd运行程序的时候将其终止。

#!/usr/bin/python
# -*- coding: utf-8 -*-
import socket
import threading, time

def tcplink(sock,addr):
    print('Accept new connection from %s:%s...' %addr)
    sock.send(b'Welcome!')
    while True:
        data=sock.recv(1024)
        time.sleep(1)
        if not data or data.decode('utf-8')=='exit':
            break
        sock.send(('Hello,%s!'% data.decode('utf-8')).encode('utf-8'))
    sock.close()
    print('Connection from %s:%s closed.' % addr)
    
s=socket.socket()
s.bind(('127.0.0.1',1234))
s.listen(5)
print('Waiting for conection...')

while True:
    #accept a new connection
    sock,addr=s.accept()
    #create a new thread
    t=threading.Thread(target=tcplink,args=(sock,addr))
    t.start()

在win10上的cmd运行后的情况是按ctrl+c,ctrl+z,ctrl+d都不能终止,请问要怎么终止程序?

黄舟
黄舟

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Antworte allen(6)
迷茫

Ctrl + C

PHPzhong

在启动线程之前,添加 setDaemon(True)

while True:
    #accept a new connection
    sock,addr=s.accept()
    #create a new thread
    t=threading.Thread(target=tcplink,args=(sock,addr))
    t.setDaemon(True)  # <-- add this
    t.start()
    

daemon

A boolean value indicating whether this thread is a daemon
thread (True) or not (False). This must be set before start() is
called, otherwise RuntimeError is raised. Its initial value is
inherited from the creating thread; the main thread is not a daemon
thread and therefore all threads created in the main thread default to
daemon = False.

The entire Python program exits when no alive non-daemon threads are
left.

这样 <C-c> 的中断信号就会被 rasie。

阿神
kill -9
小葫芦

关闭cmd命令窗口,重新开启一个cmd,我是这么做的。

左手右手慢动作

可以使用signal模块,当按住Ctrl+C时,捕捉信息,然后退出.

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import signal

def do_exit(signum, frame):
    print("exit ...")
    exit()

signal.signal(signal.SIGINT, do_exit)

while True:
    print("processing ...")
伊谢尔伦

我记得可以

try:
    ......
except KeyboardInterrupt:
    exit()
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