代码如下,其中getX()成功有返回结果,getY()却报异常.
public class AddressUtilDemo {
public static void main(String[] args){
AddressUtil AddressUtil = new AddressUtil();
AddressUtil.setAddress("3454.234,24l.432");
System.out.println(AddressUtil.getX());
System.out.println(AddressUtil.getY());
}
}
class AddressUtil {
private String address;
public AddressUtil(){}
public AddressUtil(String address){
if(address.indexOf(",")>0){
this.address = address;
}
}
public Double getX(){
String string = address.substring(0, address.indexOf(",")) ;
return Double.parseDouble(string);
}
public Double getY(){
String string = address.substring((address.indexOf(",")+1));
return Double.parseDouble(string);
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address.trim();
}
}
试过string.trim()等方法都无效.debug看到的string确实是预期中的数值.
以下是异常信息:
Exception in thread "main" java.lang.NumberFormatException: For input string: "24l.432"
你应该学会调试,看看getY中的string就知道问题了
24l.432
24后们是 L,不是 1
骚年,你main函数里setAddress的是3454.234,24l.432(24L,是L不是1),所以y是错的,转化失败了,建议编辑器字体用Source Code Pro 还能看的出来