objective-c - iPhone如何用编程检索内存使用?
ringa_lee
ringa_lee 2017-04-21 11:18:53
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我想以编程的方式随时检索iPhone App的内存使用量。是的,我注意到了ObjectAlloc/Leaks。但我对那些不感兴趣,只想知道是否可以通过写代码来获取所使用的字节量,并通过NSLog报告。
谢谢!

原问题:Programmatically retrieve memory usage on iPhone

ringa_lee
ringa_lee

ringa_lee

Antworte allen(1)
小葫芦

Jason Coco:
为了获得App实际使用的内存字节,你可以使用下述方式。但是,你必须要熟练掌握各种分析工具,就像它们设计了更好看的表示整体使用的图片一样。

#import <mach/mach.h>

// ...

void report_memory(void) {
  struct task_basic_info info;
  mach_msg_type_number_t size = sizeof(info);
  kern_return_t kerr = task_info(mach_task_self(),
                                 TASK_BASIC_INFO,
                                 (task_info_t)&info,
                                 &size);
  if( kerr == KERN_SUCCESS ) {
    NSLog(@"Memory in use (in bytes): %u", info.resident_size);
  } else {
    NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
  }
}

info.virtual_size中有个字段可以告诉你可用的虚拟内存的具体字节数(或者任何情况下内存分配给App的潜在虚拟内存)。Pgb链接的代码将为你提供设备的可用内存和内存类型。


Douglas K. Bell:
这是加强后的report_memory(),可以在NSLog()中迅速显示内存泄漏。

void report_memory(void) {
    static unsigned last_resident_size=0;
    static unsigned greatest = 0;
    static unsigned last_greatest = 0;

    struct task_basic_info info;
    mach_msg_type_number_t size = sizeof(info);
    kern_return_t kerr = task_info(mach_task_self(),
                               TASK_BASIC_INFO,
                               (task_info_t)&info,
                               &size);
    if( kerr == KERN_SUCCESS ) {
        int diff = (int)info.resident_size - (int)last_resident_size;
        unsigned latest = info.resident_size;
        if( latest > greatest   )   greatest = latest;  // track greatest mem usage
        int greatest_diff = greatest - last_greatest;
        int latest_greatest_diff = latest - greatest;
        NSLog(@"Mem: %10u (%10d) : %10d :   greatest: %10u (%d)", info.resident_size, diff,
          latest_greatest_diff,
          greatest, greatest_diff  );
    } else {
        NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
    }
    last_resident_size = info.resident_size;
    last_greatest = greatest;
}
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