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javascript - 下拉列表选择后无法变成已选择项

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Release: 2016-06-06 20:18:02
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1.下拉列表选择后没有地址栏有相应的参数,数据也能查询出来但是下拉列表未能变成已选择项

html :

<code>            <div class="control-group">
                <label class="control-label span4">品牌:</label>
                <select class="m-wrap span8" id="disbrand">
                <option value="">请选择品牌</option>
                <?php foreach($brands as $v){?>
                <option value="<?php echo $v['brand_id']?>" echo isset :>>  <?php echo $v['brand_name']?>
</option>
                <?php }?>
                </select>
            </div>
        </code>
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js :function dissearch(){

<code>var url = "/console/distribute/distribute/index/";
var agt = "?";
if($("#disbrand").val()!=""){
    url+=agt+"brand_id="+$("#disbrand").val();
    agt = "&";
}
</code>
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  1. 贴上报错信息

  2. 贴上相关截图javascript - 下拉列表选择后无法变成已选择项

  3. 已经尝试过哪些方法仍然没解决(附上相关链接)

回复内容:

1.下拉列表选择后没有地址栏有相应的参数,数据也能查询出来但是下拉列表未能变成已选择项

html :

<code>            <div class="control-group">
                <label class="control-label span4">品牌:</label>
                <select class="m-wrap span8" id="disbrand">
                <option value="">请选择品牌</option>
                <?php foreach($brands as $v){?>
                <option value="<?php echo $v['brand_id']?>" echo isset :>>  <?php echo $v['brand_name']?>
</option>
                <?php }?>
                </select>
            </div>
        </code>
Copy after login
Copy after login

js :function dissearch(){

<code>var url = "/console/distribute/distribute/index/";
var agt = "?";
if($("#disbrand").val()!=""){
    url+=agt+"brand_id="+$("#disbrand").val();
    agt = "&";
}
</code>
Copy after login
Copy after login
  1. 贴上报错信息

  2. 贴上相关截图javascript - 下拉列表选择后无法变成已选择项

  3. 已经尝试过哪些方法仍然没解决(附上相关链接)

就是不知道你这个$args['brand_id']是否存在了,你先var_dump出来看看,实在不行的话,那个SELECTED改为selected="selected"

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