XML节点提取问题

WBOY
Release: 2016-06-06 20:18:25
Original
1368 people have browsed it

现有的PHP代码输出XML节点时,只能输出第一个同名节点内容"100". 请问怎样才能输出所有节点的内容呢?

现有代码见下:
/* $xmlstring 原内容:
**

-
id*cn
100
101
102
103
105
**
*/

$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
foreach ($users as $user) {
$html .= 'outputCustomer:'.get_txt($user,'Customer').'
';
$html .= 'outputGeo:'.get_txt($user,'GeocallCLI').'
';
}
echo $html;

function get_txt($parent, $name) {
$nodes = $parent->getElementsByTagName($name);
return $nodes->item(0)->nodeValue;
}
?>

回复内容:

现有的PHP代码输出XML节点时,只能输出第一个同名节点内容"100". 请问怎样才能输出所有节点的内容呢?

现有代码见下:
/* $xmlstring 原内容:
**

-
id*cn
100
101
102
103
105
**
*/

$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
foreach ($users as $user) {
$html .= 'outputCustomer:'.get_txt($user,'Customer').'
';
$html .= 'outputGeo:'.get_txt($user,'GeocallCLI').'
';
}
echo $html;

function get_txt($parent, $name) {
$nodes = $parent->getElementsByTagName($name);
return $nodes->item(0)->nodeValue;
}
?>

最后一行代码

<code>return $nodes->item(0)->nodeValue;</code>
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因为只返回item(0)
所以只看得到一个100
只需检测$nodes的长度,循环输出即可
代码

<code><?php $xmlstring = '<?xml version="1.0"?>

<getuserinfo>
<customer>id*cn</customer>
<geocallcli>100</geocallcli>
<geocallcli>101</geocallcli>
<geocallcli>102</geocallcli>
<geocallcli>103</geocallcli>
<geocallcli>105</geocallcli>
</getuserinfo>';

$xmldoc = new DOMDocument();
$xmldoc->loadXML($xmlstring);
$users = $xmldoc->getElementsByTagName('GetUserInfo');
$html  = '';
foreach ($users as $user) {
    $html .= get_txt($user, 'Customer') . '
';
    $html .= get_txt($user, 'GeocallCLI') . '
';
}
echo $html;

function get_txt($parent, $name)
{
    $nodes = $parent->getElementsByTagName($name);
    
    $data = '';
    for ($i = 0; $i length; $i++) {
        $data .= 'output' . $name . ':' . $nodes->item($i)->nodeValue . '<br>';
    }
    return $data;
}
?></code>
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可否代码示例,谢谢!

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