直接这样$_COOKIE['username'] 不能打印出来登陆的用户名啊 我想用这个用户名怎么办呢?
登录页
<code><?php $pdo=new PDO("mysql:host=localhost;dbname=t1;","root",""); if(isset($_POST['submit'])){ $stmt=$pdo->prepare("select id,username,password from user where username=? and password=?"); $stmt->execute(array($_POST['username'],($_POST['password']))); if($stmt->rowCount()>0){ list($id,$username)=$stmt->fetch(PDO::FETCH_NUM); $time=time()+24*60*60; setCookie("uid",$id,$time,"/"); setCookie("username",$username,$time,"/"); setCookie("isLogin",1,$time,"/"); echo '<script>location="blog.php"</script>'; } else{ echo "登陆失败"; } } ?> <form action="login.php" method="post"> 用户名:<input type="text" name="username"> 密码:<input type="text" name="password"> <button type="submit" name="submit">登录</button> </form> </code>
直接这样$_COOKIE['username'] 不能打印出来登陆的用户名啊 我想用这个用户名怎么办呢?
登录页
<code><?php $pdo=new PDO("mysql:host=localhost;dbname=t1;","root",""); if(isset($_POST['submit'])){ $stmt=$pdo->prepare("select id,username,password from user where username=? and password=?"); $stmt->execute(array($_POST['username'],($_POST['password']))); if($stmt->rowCount()>0){ list($id,$username)=$stmt->fetch(PDO::FETCH_NUM); $time=time()+24*60*60; setCookie("uid",$id,$time,"/"); setCookie("username",$username,$time,"/"); setCookie("isLogin",1,$time,"/"); echo '<script>location="blog.php"</script>'; } else{ echo "登陆失败"; } } ?> <form action="login.php" method="post"> 用户名:<input type="text" name="username"> 密码:<input type="text" name="password"> <button type="submit" name="submit">登录</button> </form> </code>
你得先在登录成功的时候写一下COOKIE,写完了再访问新的页面,你的php代码才能读到它
没人啊。。。。。。。。。。