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php怎么返回JSON数据

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Release: 2020-06-11 10:03:04
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php怎么返回JSON数据

php怎么返回JSON?

php返回json,xml,JSONP等格式的数据

返回json数据:

header('Content-Type:application/json; charset=utf-8');
$arr = array('a'=>1,'b'=>2);
exit(json_encode($arr));
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注意:如果不加header直接输出json_encode的值的话,返回的是字符串不是对象,js那边就需要先eval('('+data+')')转化为对象,在取值

返回xml数据:

header('Content-Type:text/xml; charset=utf-8');
exit($xml);
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返回jsonp数据:

$arr = array('a'=>1, 'b'=>2, 'c'=>3);
$json = json_encode($arr);
$callback = $_GET['callback'];
exit($callback."($json)");
//注意callback是js传过来的参数名称
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thinkphp如何返回各种数据:

$this->ajaxReturn (json_encode($arr),'JSON');
$this->ajaxReturn (json_encode($arr),'JSONP');
$this->ajaxReturn (json_encode($arr),'XML');
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json_encode有个参数禁止unicode编码

JSON_UNESCAPED_UNICODE
json_encode('中文',JSON_UNESCAPED_UNICODE);
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默认中文编码

header('Content-Type:application/json; charset=gbk');
$data = $db->select($sql);
$data = json_encode($data);
$data=preg_replace("#\\\u([0-9a-f]{4})#ie", "iconv('UCS-2BE', 'gbk', pack('H4', '\\1'))", $data);
 exit($data);
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更多相关知识,请访问PHP中文网

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