怎么给类中的属性赋值?

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Release: 2016-06-06 20:24:23
Original
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class a{
public $x = $b;
return $x;
}

$q="asdffg";
$z=new a();


怎么给a类中的$b,赋值$q的内容呢?

回复内容:

class a{
public $x = $b;
return $x;
}

$q="asdffg";
$z=new a();


怎么给a类中的$b,赋值$q的内容呢?

<code>$z->b = $q</code>
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