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Home Backend Development PHP Tutorial mysql查询将两列数值相加问题

mysql查询将两列数值相加问题

Jun 06, 2016 pm 08:33 PM
mysql php sql

如图所示:
我希望加一个total_price列,值为price+price2的和,这个应该怎么写SQL;

select * from ims_goods_1 where price!=0 and price2!=0;

mysql查询将两列数值相加问题

奉上SQL文件:

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<code>/*

Navicat MySQL Data Transfer

 

Source Server         : car

Source Server Version : 50518

Source Host           : wsy19950503.mysql.rds.aliyuncs.com:3306

Source Database       : car

 

Target Server Type    : MYSQL

Target Server Version : 50518

File Encoding         : 65001

 

Date: 2015-06-11 15:40:28

*/

 

SET FOREIGN_KEY_CHECKS=0;

 

-- ----------------------------

-- Table structure for `ims_goods_1`

-- ----------------------------

DROP TABLE IF EXISTS `ims_goods_1`;

CREATE TABLE `ims_goods_1` (

  `id` int(4) NOT NULL AUTO_INCREMENT,

  `type` tinyint(1) NOT NULL COMMENT '1为小保养,2为电瓶',

  `name` varchar(255) NOT NULL DEFAULT '' COMMENT '商品名称',

  `price` int(4) NOT NULL COMMENT '产品价格',

  `price2` int(4) NOT NULL,

  PRIMARY KEY (`id`)

) ENGINE=MyISAM AUTO_INCREMENT=14 DEFAULT CHARSET=utf8;

 

-- ----------------------------

-- Records of ims_goods_1

-- ----------------------------

INSERT INTO `ims_goods_1` VALUES ('1', '1', '曼牌Mann', '70', '0');

INSERT INTO `ims_goods_1` VALUES ('2', '1', '马勒', '29', '0');

INSERT INTO `ims_goods_1` VALUES ('13', '1', '汉格斯特Hengsr', '68', '0');

INSERT INTO `ims_goods_1` VALUES ('4', '2', '嘉实多 金嘉护SN 10W-40', '152', '0');

INSERT INTO `ims_goods_1` VALUES ('5', '2', '嘉实多 磁护SN 5W-40', '248', '110');

INSERT INTO `ims_goods_1` VALUES ('6', '2', '嘉实多 极护SN 0W-40', '376', '125');

INSERT INTO `ims_goods_1` VALUES ('7', '2', '壳牌 黄喜力HX5 10W-40', '138', '0');

INSERT INTO `ims_goods_1` VALUES ('8', '2', '壳牌  灰喜力ULTRA 5W-40', '380', '0');

INSERT INTO `ims_goods_1` VALUES ('10', '2', '美孚 美孚1号 0W-40', '368', '113');

 

</code>

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回复内容:

如图所示:
我希望加一个total_price列,值为price+price2的和,这个应该怎么写SQL;

select * from ims_goods_1 where price!=0 and price2!=0;

mysql查询将两列数值相加问题

奉上SQL文件:

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

19

20

21

22

23

24

25

26

27

28

29

30

31

32

33

34

35

36

37

38

39

40

41

42

43

44

<code>/*

Navicat MySQL Data Transfer

 

Source Server         : car

Source Server Version : 50518

Source Host           : wsy19950503.mysql.rds.aliyuncs.com:3306

Source Database       : car

 

Target Server Type    : MYSQL

Target Server Version : 50518

File Encoding         : 65001

 

Date: 2015-06-11 15:40:28

*/

 

SET FOREIGN_KEY_CHECKS=0;

 

-- ----------------------------

-- Table structure for `ims_goods_1`

-- ----------------------------

DROP TABLE IF EXISTS `ims_goods_1`;

CREATE TABLE `ims_goods_1` (

  `id` int(4) NOT NULL AUTO_INCREMENT,

  `type` tinyint(1) NOT NULL COMMENT '1为小保养,2为电瓶',

  `name` varchar(255) NOT NULL DEFAULT '' COMMENT '商品名称',

  `price` int(4) NOT NULL COMMENT '产品价格',

  `price2` int(4) NOT NULL,

  PRIMARY KEY (`id`)

) ENGINE=MyISAM AUTO_INCREMENT=14 DEFAULT CHARSET=utf8;

 

-- ----------------------------

-- Records of ims_goods_1

-- ----------------------------

INSERT INTO `ims_goods_1` VALUES ('1', '1', '曼牌Mann', '70', '0');

INSERT INTO `ims_goods_1` VALUES ('2', '1', '马勒', '29', '0');

INSERT INTO `ims_goods_1` VALUES ('13', '1', '汉格斯特Hengsr', '68', '0');

INSERT INTO `ims_goods_1` VALUES ('4', '2', '嘉实多 金嘉护SN 10W-40', '152', '0');

INSERT INTO `ims_goods_1` VALUES ('5', '2', '嘉实多 磁护SN 5W-40', '248', '110');

INSERT INTO `ims_goods_1` VALUES ('6', '2', '嘉实多 极护SN 0W-40', '376', '125');

INSERT INTO `ims_goods_1` VALUES ('7', '2', '壳牌 黄喜力HX5 10W-40', '138', '0');

INSERT INTO `ims_goods_1` VALUES ('8', '2', '壳牌  灰喜力ULTRA 5W-40', '380', '0');

INSERT INTO `ims_goods_1` VALUES ('10', '2', '美孚 美孚1号 0W-40', '368', '113');

 

</code>

Copy after login
Copy after login

select t.*,price+price2 as total_price from ims_goods_1 t where price!=0 and price2!=0;

如果这里的+换成一个比较复杂的运算,比如求这两个数的阶乘的和作为新的列,这个该怎么弄

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