Laravel中控制器实例化model的方法有什么不妥 请指点
我在每个控制器的初始化方法中实例化了相应的Model,然后在各个方法里使用,不知道这样有什么不妥,感觉自己实现的不够优雅。 主要是网站有很多模块,都是差不多的功能,部分代码是替换了model名称实例化。
<code>public function __construct() { parent::__construct(); $this->model = new \Line(); } public function store() { $input = \Input::all(); $validator = \Validator::make($input,$this->model->getRules('create'),$this->model->getMessage()); if ($validator->fails()) { return \Redirect::back()->with('errorCode',1)->withErrors($validator)->withInput(); }else{ if($model = $this->model->create($input)){ return \Redirect::back()->with('errorCode',0); }else{ return \Redirect::back()->with('errorCode',2); } } } </code>
回复内容:
我在每个控制器的初始化方法中实例化了相应的Model,然后在各个方法里使用,不知道这样有什么不妥,感觉自己实现的不够优雅。 主要是网站有很多模块,都是差不多的功能,部分代码是替换了model名称实例化。
<code>public function __construct() { parent::__construct(); $this->model = new \Line(); } public function store() { $input = \Input::all(); $validator = \Validator::make($input,$this->model->getRules('create'),$this->model->getMessage()); if ($validator->fails()) { return \Redirect::back()->with('errorCode',1)->withErrors($validator)->withInput(); }else{ if($model = $this->model->create($input)){ return \Redirect::back()->with('errorCode',0); }else{ return \Redirect::back()->with('errorCode',2); } } } </code>
如果是Model的话,不需要这样做。
你是store可以这样写:
<code>public function store() { $input = \Input::all(); $validator = \Validator::make($input, Line::getRules('create'), Line::getMessage()); if ($validator->fails()) { return \Redirect::back()->with('errorCode',1)->withErrors($validator)->withInput(); }else{ if($model = Line::create($input)){ return \Redirect::back()->with('errorCode',0); }else{ return \Redirect::back()->with('errorCode',2); } } } </code>
Lind的getRules和getMessage和具体的对象没有关系的话,就写成静态方法。
下面的create直接用静态方法。

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