为什么从url中直接传递"n"没办法换行?
问题一
<code><?php echo $_GET['input'];?> </code>
input=start__\n__end
:不可以换行input=start__%0a__end
:可以换行
注:关于这个问题,谁能从PHP解释器的角度来说明下吗?
问题二
<code><script> //console.log("<?php echo $_GET["input"]?>"); </script> </code>
这种情况,在input=%0a
的时候可以换行
但是,我们知道,Unicode的值为:2028的时候(即:\u2028
),表示行分隔符,但input=\u2028
却没法换行?
回复内容:
问题一
<code><?php echo $_GET['input'];?> </code>
input=start__\n__end
:不可以换行input=start__%0a__end
:可以换行
注:关于这个问题,谁能从PHP解释器的角度来说明下吗?
问题二
<code><script> //console.log("<?php echo $_GET["input"]?>"); </script> </code>
这种情况,在input=%0a
的时候可以换行
但是,我们知道,Unicode的值为:2028的时候(即:\u2028
),表示行分隔符,但input=\u2028
却没法换行?
第一个问题:
url 编码是使用 %
来转义的,不是 \
,所以 \
在 url 里面只是个平凡的字符而已。
PHP 在处理 query string 的时候会自动根据 url 规范进行转义处理,$_GET
存储是处理过的值,所以要想表示特殊字符,得在 url 里面使用 %
做转移才有效。
第二个问题:
input=%0a
才能输出换行符的原因上面已经解释了。
至于换行符,由于 url 里面是 utf8 编码,\u2028
对应的 utf8 编码是 %E2%80%A8
,所以input=%E2%80%A8
就能达到想要的效果了。

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