关于PHP中时间计算的"-1 month"?
今天,也就是10月31号,执行一下代码:
<code>echo date('Ym', strtotime("-1 month")); </code>
返回的结果是201410,是不是说明类似strtotime("-1 month")
是不可信的?
定义了时区。
php -v
PHP 5.4.33-1~dotdeb.0 (cli) (built: Sep 19 2014 12:00:21)
Copyright (c) 1997-2014 The PHP Group
Zend Engine v2.4.0, Copyright (c) 1998-2014 Zend Technologies
回复内容:
今天,也就是10月31号,执行一下代码:
<code>echo date('Ym', strtotime("-1 month")); </code>
返回的结果是201410,是不是说明类似strtotime("-1 month")
是不可信的?
定义了时区。
php -v
PHP 5.4.33-1~dotdeb.0 (cli) (built: Sep 19 2014 12:00:21)
Copyright (c) 1997-2014 The PHP Group
Zend Engine v2.4.0, Copyright (c) 1998-2014 Zend Technologies
<code>case TIMELIB_MONTH: s->time->relative.m += amount * relunit->multiplier; break; 月份直接减1 ,当前日期 10月 31号 减一变成 9月31号 即是 10月1号 </code>
这个是php bug,你可以指定月的开始时间。
$base = strtotime(date('Y-m',time()) . '-01 00:00:01');
echo date('m/Y',strtotime('-1 month', $base));
不定义时区真的大丈夫么?定义时区后我这边是正常的,PHP5.5环境。
<code>date_default_timezone_set("Asia/Shanghai"); echo date("Y-m", strtotime("-1 month")); </code>
可能真的如 @美丽的格调 所说是个BUG(看了下手册不知道是不是5.2.7之处的那个BUG),按照他的说法定义了相对时间后正常了。
<code>echo date("Y-m", strtotime("-1 month", strtotime("first day of this month"))); </code>

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