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一个php if判断问题

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Release: 2016-06-06 20:44:49
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今天做一个if判断是出现问题

<code>$sn=1;
if($sn=='1'){echo "aaa"}
</code>
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Copy after login

代码无法显示“aaa”,请问哪里出错了?

回复内容:

今天做一个if判断是出现问题

<code>$sn=1;
if($sn=='1'){echo "aaa"}
</code>
Copy after login
Copy after login

代码无法显示“aaa”,请问哪里出错了?

  1. 代码第2行少了一个分号,如果设置了display_errors = off的话因为有错误会无法执行而且也不会报错。可以在最开头设置ini_set("display_errors", "on");试试。

  2. 补全分号后代码没有问题,无图无真相:

    一个php if判断问题

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