<code class="lang-javascript"> var uinfo = {}; var uname = document.getElementById('uname'); var upwd = document.getElementById('upwd'); uinfo['uname'] = uname.value; uinfo['upwd'] = upwd.value; var usent = JSON.stringify(uinfo); var xhr = null; if(window.XMLHttpRequest){ xhr = new XMLHttpRequest(); }else{ xhr = ActiveXObject('Microsoft.XMLHttp'); } xhr.open("POST", "/controler/login.php",true); //etc xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); xhr.send(usent); </code>
然后php端怎么接受js发送的数据呢?
$_POST['']
拿不到数据,这部分的格式具体是要指定呢,求大神指导下~~
多谢~!
<code class="lang-javascript"> var uinfo = {}; var uname = document.getElementById('uname'); var upwd = document.getElementById('upwd'); uinfo['uname'] = uname.value; uinfo['upwd'] = upwd.value; var usent = JSON.stringify(uinfo); var xhr = null; if(window.XMLHttpRequest){ xhr = new XMLHttpRequest(); }else{ xhr = ActiveXObject('Microsoft.XMLHttp'); } xhr.open("POST", "/controler/login.php",true); //etc xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); xhr.send(usent); </code>
然后php端怎么接受js发送的数据呢?
$_POST['']
拿不到数据,这部分的格式具体是要指定呢,求大神指导下~~
多谢~!
答案太弱了...
<code>xhr.send('json='+usent); </code>
你可以用file_get_contents(‘php://input’)
;尝试打印看看是什么,可以去看看这一篇文章