程序员 - PHP时间问题,2014-1-21 和 2013-5-13 请用最有效率的方法计算出两个时间相差的年份和月份??

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Release: 2016-06-06 20:46:42
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PHP时间问题,2014-1-21 和 2013-5-13 请用最有效率的方法计算出两个时间相差的年份和月份??年份和月份用int类型表示

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PHP时间问题,2014-1-21 和 2013-5-13 请用最有效率的方法计算出两个时间相差的年份和月份??年份和月份用int类型表示

https://github.com/briannesbitt/Carbon

<code>$dt1 = Carbon\Carbon::createFromDate(2014, 1, 21);
$dt2 = Carbon\Carbon::createFromDate(2013, 5, 13);

echo $dt1->diffInYears($dt2);    //0
echo $dt1->diffInMonths($dt2);    //8
echo $dt1->diffInDays($dt2);    //253
echo $dt1->diffInHours($dt2);    //6072
echo $dt1->diffInMinutes($dt2);    //364320
echo $dt1->diffInSeconds($dt2);    //21859200
</code>
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是截至到2014-1-21的00:00:00还是到23:59:59


1.

<code class="lang-php">echo (new DateTime('2014-3-15'))->diff(new DateTime('2014-5-10'))->format('两个时间相差 %y 年 %m 月 %d 天.');
</code>
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2.

<code class="lang-php">$ts1 = strtotime('2014-3-15');
$ts2 = strtotime('2014-5-10');
$ts = $ts1 > $ts2 ? $ts1 - $ts2 : $ts2 - $ts1;
echo (new DateInterval($ts))->format('两个时间相差 %y 年 %m 月 %d 天.');
</code>
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