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mysql - php获取json的问题

Jun 06, 2016 pm 08:48 PM
highcharts json mysql php

现在我的问题是,我正在使用highChart,其中它的一个属性为series,要使用到外部数据。我准备使用php从数据库中获取数据使用json。

serise属性中的data格式为

<code>[{
        name: 'Tokyo',
        data: [7.0, 6.9, 9.5, 14.5, 18.2, 21.5, 25.2, 26.5, 23.3, 18.3, 13.9, 9.6]
    }, {
        name: 'New York',
        data: [-0.2, 0.8, 5.7, 11.3, 17.0, 22.0, 24.8, 24.1, 20.1, 14.1, 8.6, 2.5]
    }, {
        name: 'Berlin',
        data: [-0.9, 0.6, 3.5, 8.4, 13.5, 17.0, 18.6, 17.9, 14.3, 9.0, 3.9, 1.0]
    }, {
        name: 'London',
        data: [3.9, 4.2, 5.7, 8.5, 11.9, 15.2, 17.0, 16.6, 14.2, 10.3, 6.6, 4.8]
    }]
</code>
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但是数据库中的获取data时是这样的,一个字段对应一个name,字段下的所有数据对应于data,问题就是如何获取这些数据,因为拼接成这样的json数组的话,发现不太好做。 另外,我使用js直接获取了表单中td的数据,组装成了这种格式的json,直接在series上调用js方法,发现不行。是不是因为要么直接在data域中放数据,要么在name、data等后面放数据,而不是把这个格式的数据放入series中。

回复内容:

现在我的问题是,我正在使用highChart,其中它的一个属性为series,要使用到外部数据。我准备使用php从数据库中获取数据使用json。

serise属性中的data格式为

<code>[{
        name: 'Tokyo',
        data: [7.0, 6.9, 9.5, 14.5, 18.2, 21.5, 25.2, 26.5, 23.3, 18.3, 13.9, 9.6]
    }, {
        name: 'New York',
        data: [-0.2, 0.8, 5.7, 11.3, 17.0, 22.0, 24.8, 24.1, 20.1, 14.1, 8.6, 2.5]
    }, {
        name: 'Berlin',
        data: [-0.9, 0.6, 3.5, 8.4, 13.5, 17.0, 18.6, 17.9, 14.3, 9.0, 3.9, 1.0]
    }, {
        name: 'London',
        data: [3.9, 4.2, 5.7, 8.5, 11.9, 15.2, 17.0, 16.6, 14.2, 10.3, 6.6, 4.8]
    }]
</code>
Copy after login
Copy after login

但是数据库中的获取data时是这样的,一个字段对应一个name,字段下的所有数据对应于data,问题就是如何获取这些数据,因为拼接成这样的json数组的话,发现不太好做。 另外,我使用js直接获取了表单中td的数据,组装成了这种格式的json,直接在series上调用js方法,发现不行。是不是因为要么直接在data域中放数据,要么在name、data等后面放数据,而不是把这个格式的数据放入series中。

<code><?php $arr[0]['name'] = 'Tokyo';
$arr[0]['data'] = array( 7.0, 6.9, 9.5, 14.5, 18.2, 21.5, 25.2, 26.5, 23.3, 18.3, 13.9, 9.6 );

$arr[1]['name'] = 'New York';
$arr[1]['data'] = array( -0.2, 0.8, 5.7, 11.3, 17.0, 22.0, 24.8, 24.1, 20.1, 14.1, 8.6, 2.5 );

$arr[2]['name'] = 'Berlin';
$arr[2]['data'] = array( -0.9, 0.6, 3.5, 8.4, 13.5, 17.0, 18.6, 17.9, 14.3, 9.0, 3.9, 1.0 );

$arr[3]['name'] = 'London';
$arr[3]['data'] = array( 3.9, 4.2, 5.7, 8.5, 11.9, 15.2, 17.0, 16.6, 14.2, 10.3, 6.6, 4.8 );

echo json_encode($arr);
</code></code>
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你把这段代码打印出来试试(结果和你的示例的结果是一样的),跟这个数组格式一样的再json_encode一下就得到了要求的格式了。


你的评论提到的问题应该是一个MySQL的问题,我一般是这么操作的。

<code>$sql = mysql_query('我是SQL请求语句');
while ($item = mysql_fetch_array($sql)) {
    $data[]['name'] = $item['name'];
    //balba
}
</code>
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大概就是这个样子,用while循环获取。

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